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Number of Questions: 20
Time: 20 Minutes
Category: Aptitude
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Question 1 of 20
1. Question
Find the lowest common multiple of 24,36 and 40
Correct
LCM =2*2*2*3*3*5=360
Incorrect
LCM =2*2*2*3*3*5=360

Question 2 of 20
2. Question
The GCD of 1.08, 0.36 and 0.9 is
Correct
Given numbers are 1.08, 0.36, and 0.90
HCF of 108, 36, and 90 is 18
Then HCF of given numbers =0.18
Incorrect
Given numbers are 1.08, 0.36, and 0.90
HCF of 108, 36, and 90 is 18
Then HCF of given numbers =0.18

Question 3 of 20
3. Question
Three numbers are in the ratio 1:2:3 and their HCF is 12.The numbers are:
Correct
Let the required numbers be x, 2x, 3x.Then their HCF=x. So x=12
The numbers are 12, 24, and 36.
Incorrect
Let the required numbers be x, 2x, 3x.Then their HCF=x. So x=12
The numbers are 12, 24, and 36.

Question 4 of 20
4. Question
The sum of two numbers is 216 and their HCF is 27.The numbers are:
Correct
Let the required numbers be 27a and 27b.Then 27a+27b=216 => a+b=8
Now, coprime with sum 8 are (1, 7) and (3, 5).
Required numbers are (27*1, 27*7) and (27*3, 27*5) i.e. (27,189) and (81,135)
Out of these, the given one is the answer is the pair (27,189).
Incorrect
Let the required numbers be 27a and 27b.Then 27a+27b=216 => a+b=8
Now, coprime with sum 8 are (1, 7) and (3, 5).
Required numbers are (27*1, 27*7) and (27*3, 27*5) i.e. (27,189) and (81,135)
Out of these, the given one is the answer is the pair (27,189).

Question 5 of 20
5. Question
The product of two numbers is 2028 and their HCF is 13.The number of such pairs is :
Correct
Let the numbers be 13a and 13b.Then 13a*13b=2028 => ab=12
Now, coprimes with product 12 are (1, 12) and (3, 4).
So, the required numbers are (13*1, 13*12) and (13*3,13*4)
Clearly there are 2 such pairs.
Incorrect
Let the numbers be 13a and 13b.Then 13a*13b=2028 => ab=12
Now, coprimes with product 12 are (1, 12) and (3, 4).
So, the required numbers are (13*1, 13*12) and (13*3,13*4)
Clearly there are 2 such pairs.

Question 6 of 20
6. Question
The HCF of two numbers is 11 and their LCM is 7700.If one of the numbers is 275,then the other is :
Correct
Product of first number and second number = HCF * LCM
Second number= (HCF * LCM)/First number
Second number = (11*7700)/275=308.
Incorrect
Product of first number and second number = HCF * LCM
Second number= (HCF * LCM)/First number
Second number = (11*7700)/275=308.

Question 7 of 20
7. Question
The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively is :
Correct
Required number
=HCF of (16576) and (20375)
=HCF of 1651 and 2032 =127
Incorrect
Required number
=HCF of (16576) and (20375)
=HCF of 1651 and 2032 =127

Question 8 of 20
8. Question
Three different containers 496 litres, 403 litres and 713 litres of mixtures of milk and water respectively .What biggest measure can measure all the different quantities exactly?
Correct
Required measurement = (HCF of 496,403,713) litres=31 litres
Incorrect
Required measurement = (HCF of 496,403,713) litres=31 litres

Question 9 of 20
9. Question
The greatest possible length which can be used to measure exactly the length 7 m , 3m 85 cm,12 m 95 cm is :
Correct
Required length =HCF of 700 cm 385 cm, 1295 cm = 35 cm.
Incorrect
Required length =HCF of 700 cm 385 cm, 1295 cm = 35 cm.

Question 10 of 20
10. Question
Which of the following is a pair of coprime?
Correct
HCF of 18 and 25 is 1.So they are coprime.
Incorrect
HCF of 18 and 25 is 1.So they are coprime.

Question 11 of 20
11. Question
Two numbers are in the ratio of 15:11. If their H.C.F. is 13, find the numbers.
Correct
Let the required numbers be 15.x and llx.
Then, their H.C.F. is x. So, x = 13.
The numbers are (15 x 13 and 11 x 13) i.e., 195 and 143.
Incorrect
Let the required numbers be 15.x and llx.
Then, their H.C.F. is x. So, x = 13.
The numbers are (15 x 13 and 11 x 13) i.e., 195 and 143.

Question 12 of 20
12. Question
Find the greatest possible length which can be used to measure exactly the lengths 4 m 95 cm, 9 m and 16 m 65 cm
Correct
Required length = H.C.F. of 495 cm, 900 cm and 1665 cm.
495 = 3^{2} x 5 x 11, 900 = 2^{2} x 3^{2} x 5^{2}, 1665 = 3^{2} x 5 x 37.
\H.C.F. = 32 x 5 = 45.
Hence, required length = 45 cm.
Incorrect
Required length = H.C.F. of 495 cm, 900 cm and 1665 cm.
495 = 3^{2} x 5 x 11, 900 = 2^{2} x 3^{2} x 5^{2}, 1665 = 3^{2} x 5 x 37.
\H.C.F. = 32 x 5 = 45.
Hence, required length = 45 cm.

Question 13 of 20
13. Question
Find the greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively
Correct
Incorrect

Question 14 of 20
14. Question
Find the largest number which divides 62, 132 and 237 to leave the same remainder in each case.
Correct
Required number = H.C.F. of (132 – 62), (237 – 132) and (237 – 62)
= H.C.F. of 70, 105 and 175 = 35.
Incorrect
Required number = H.C.F. of (132 – 62), (237 – 132) and (237 – 62)
= H.C.F. of 70, 105 and 175 = 35.

Question 15 of 20
15. Question
Which of the following has the most number of divisors?
Correct
Option A, 176 = 1 x 2 x 2 x 2 x 2 x 11.
Option B, 182 = 1 x 2 x 7 x 13.
Option C, 99 = 1 x 3 x 3 x 11.
Option D, 101 = 1 x 101.
Divisors of 99 are 1, 3, 9, 11, 33, 99.
Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176.
Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182..
Hence, 176 have the most number of divisors..
Incorrect
Option A, 176 = 1 x 2 x 2 x 2 x 2 x 11.
Option B, 182 = 1 x 2 x 7 x 13.
Option C, 99 = 1 x 3 x 3 x 11.
Option D, 101 = 1 x 101.
Divisors of 99 are 1, 3, 9, 11, 33, 99.
Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176.
Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182..
Hence, 176 have the most number of divisors..

Question 16 of 20
16. Question
252 can be expressed as a product of primes as:
Correct
Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Incorrect
Clearly, 252 = 2 x 2 x 3 x 3 x 7.

Question 17 of 20
17. Question
The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:
Correct
L.C.M. of 5, 6, 7, 8 = 840.
Required number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2.
Required number = (840 x 2 + 3) = 1683.
Incorrect
L.C.M. of 5, 6, 7, 8 = 840.
Required number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2.
Required number = (840 x 2 + 3) = 1683.

Question 18 of 20
18. Question
The least multiple of 25 which when divided by 16, 24 and 28 leaves remainder 7, 10, 13 respectively Is
Correct
Incorrect

Question 19 of 20
19. Question
The H.C.F of two numbers is 29 and other two factors of their L.C.M is 17 and 19. The larger of two Numbers is?
Correct
Incorrect

Question 20 of 20
20. Question
Least perfect number divisible by 4,9, and 5 is?
Correct
Incorrect