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Number of Questions: 20
Time: 20 Minutes
Category: Aptitude
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Question 1 of 20
1. Question
Which number would replace the question mark in series
7,12,19,?,39Correct
Answer: Option B
Explanation:
Pattern is , +5, +7, +9
Missing Number = 19+9 = 28Incorrect
Answer: Option B
Explanation:
Pattern is , +5, +7, +9
Missing Number = 19+9 = 28 
Question 2 of 20
2. Question
13, 35, 57, 79, 911, ?
Correct
Answer: Option C
Explanation:
The terms of the given series are numbers formed by joining together consecutive odd numbers in order i.e. 1 and 3, 3 and 5, 5 and 7, 7 and 9, 9 and 11, …..So, missing term = number formed by joining 11 and 13 = 1113.
Incorrect
Answer: Option C
Explanation:
The terms of the given series are numbers formed by joining together consecutive odd numbers in order i.e. 1 and 3, 3 and 5, 5 and 7, 7 and 9, 9 and 11, …..So, missing term = number formed by joining 11 and 13 = 1113.

Question 3 of 20
3. Question
In the series 2, 6, 18, 54, … what will be the 8th term ?
Correct
Answer: Option D
Explanation:
We can see the given series is in G.P.
as 2*3 = 6, 6*3 = 18, 18*3 = 54
So a = 2 , r = 3
nth term in G.P. is
ar^{n1}
= 2*3{81}
= 2*3^7
= 2*2187 = 4374Incorrect
Answer: Option D
Explanation:
We can see the given series is in G.P.
as 2*3 = 6, 6*3 = 18, 18*3 = 54
So a = 2 , r = 3
nth term in G.P. is
ar^{n1}
= 2*3{81}
= 2*3^7
= 2*2187 = 4374 
Question 4 of 20
4. Question
Look at this series: 22, 21, 23, 22, 24, 23, … What number should come next?
Correct
Answer: Option A
Explanation:
Please look carefully at the series, its pattern is,
1, +2, 1, +2, 1, so next will be +2
23+2 = 25Incorrect
Answer: Option A
Explanation:
Please look carefully at the series, its pattern is,
1, +2, 1, +2, 1, so next will be +2
23+2 = 25 
Question 5 of 20
5. Question
Look at this series: 544, 509, 474, 439, … What number should come next?
Correct
Answer: Option A
Explanation:
This is a simple subtraction series. Each number is 35 less than the previous number.
Incorrect
Answer: Option A
Explanation:
This is a simple subtraction series. Each number is 35 less than the previous number.

Question 6 of 20
6. Question
Look at this series: 72, 76, 73, 77, 74, __, 75, … What number should fill the blank?
Correct
Answer: Option D
Explanation:
This series alternates the addition of 4 with the subtraction of 3.
Incorrect
Answer: Option D
Explanation:
This series alternates the addition of 4 with the subtraction of 3.

Question 7 of 20
7. Question
The sum of first five prime numbers is:
Correct
Answer: Option D
Explanation:
Required sum = (2 + 3 + 5 + 7 + 11) = 28.
Incorrect
Answer: Option D
Explanation:
Required sum = (2 + 3 + 5 + 7 + 11) = 28.

Question 8 of 20
8. Question
On dividing a number by 56, we get 29 as remainder. On dividing the same number by 8, what will be the remainder ?
Correct
Answer: Option B
Explanation:
Formula: (Divisor*Quotient) + Remainder = Dividend.
Soln:
(56*Q)+29 = D ——(1)
D%8 = R ————(2)
From equation(2),
((56*Q)+29)%8 = R.
Assume Q = 1.
(56+29)%8 = R.
85%8 = R
5 = R.
Incorrect
Answer: Option B
Explanation:
Formula: (Divisor*Quotient) + Remainder = Dividend.
Soln:
(56*Q)+29 = D ——(1)
D%8 = R ————(2)
From equation(2),
((56*Q)+29)%8 = R.
Assume Q = 1.
(56+29)%8 = R.
85%8 = R
5 = R.

Question 9 of 20
9. Question
4, 7, 12, �.., 28, 39
Correct
ANSWER : 19
Explanation : . Series proceeds with a difference of 3, 5, 7, 9, 11, respectively. Hence, the missing number will be 19
Incorrect
ANSWER : 19
Explanation : . Series proceeds with a difference of 3, 5, 7, 9, 11, respectively. Hence, the missing number will be 19

Question 10 of 20
10. Question
4, 7, 11, 18, 29, 47, �., 123, 199
Correct
ANSWER : 76
Explanation : . 3rd number is the sum of 1st and 2nd, 4th number is the sum of 2nd and 3rd, 5th number is the sum of 3rd and 4th and so on. Hence, missing number will be 29 + 47 = 76
Incorrect
ANSWER : 76
Explanation : . 3rd number is the sum of 1st and 2nd, 4th number is the sum of 2nd and 3rd, 5th number is the sum of 3rd and 4th and so on. Hence, missing number will be 29 + 47 = 76

Question 11 of 20
11. Question
How many terms are there in 2,4,8,16……1024?
Correct
Clearly 2,4,8,16……..1024 form a GP. With a=2 and r = 4/2 =2.
Let the number of terms be n . Then
2 x 2^{n1} =1024 or 2^{n1 =512 = 2}9.
\n1=9 or n=10.
Incorrect
Clearly 2,4,8,16……..1024 form a GP. With a=2 and r = 4/2 =2.
Let the number of terms be n . Then
2 x 2^{n1} =1024 or 2^{n1 =512 = 2}9.
\n1=9 or n=10.

Question 12 of 20
12. Question
Find the sum of all 2 digit numbers divisible by 3.
Correct
All 2 digit numbers divisible by 3 are :
12, 51, 18, 21, …, 99.
This is an A.P. with a = 12 and d = 3.
Let it contain n terms. Then,
12 + (n – 1) x 3 = 99 or n = 30.
Required sum = 30/ 2 x (12+99) = 1665.
Incorrect
All 2 digit numbers divisible by 3 are :
12, 51, 18, 21, …, 99.
This is an A.P. with a = 12 and d = 3.
Let it contain n terms. Then,
12 + (n – 1) x 3 = 99 or n = 30.
Required sum = 30/ 2 x (12+99) = 1665.

Question 13 of 20
13. Question
Find the remainder when 2^{31} is divided by 5.
Correct
2^{10} = 1024. Unit digit of 2^{10} x 2^{10 }x 2^{10} is 4 [as 4 x 4 x 4 gives unit digit 4].
Unit digit of 231 is 8.
Now, 8 when divided by 5, gives 3 as remainder.
Hence, 231 when divided by 5, gives 3 as remainder.
Incorrect
2^{10} = 1024. Unit digit of 2^{10} x 2^{10 }x 2^{10} is 4 [as 4 x 4 x 4 gives unit digit 4].
Unit digit of 231 is 8.
Now, 8 when divided by 5, gives 3 as remainder.
Hence, 231 when divided by 5, gives 3 as remainder.

Question 14 of 20
14. Question
A number when divided by 342 gives a remainder 47. When the same number if divided by 19, what would be the remainder ?
Correct
On dividing the given number by 342, let k be the quotient and 47 as remainder.
Then, number – 342k + 47 = (19 x 18k + 19 x 2 + 9) = 19 (18k + 2) + 9.
\The given number when divided by 19, gives (18k + 2) as quotient and 9 as remainder.
Incorrect
On dividing the given number by 342, let k be the quotient and 47 as remainder.
Then, number – 342k + 47 = (19 x 18k + 19 x 2 + 9) = 19 (18k + 2) + 9.
\The given number when divided by 19, gives (18k + 2) as quotient and 9 as remainder.

Question 15 of 20
15. Question
Evaluate : (313 x 313 + 287 x 287).
Correct
(a^{2} + b^{2}) = 1/2 [(a + b)^{2} + (a b)^{2}]
(313)^{2} + (287)^{2} = 1/2 [(313 + 287)^{2} + (313 – 287)^{2}] = ½[(600)^{2} + (26)^{2}]
= 1/2 (360000 + 676) = 180338.
Incorrect
(a^{2} + b^{2}) = 1/2 [(a + b)^{2} + (a b)^{2}]
(313)^{2} + (287)^{2} = 1/2 [(313 + 287)^{2} + (313 – 287)^{2}] = ½[(600)^{2} + (26)^{2}]
= 1/2 (360000 + 676) = 180338.

Question 16 of 20
16. Question
Find the total number of prime factors in the expression (4)^{11} x (7)^{5} x (11)^{2}.
Correct
(4)^{11}x (7)^{5} x (11)^{2} = (2 x 2)^{11} x (7)^{5} x (11)^{2} = 2^{11} x 2^{11} x7^{5}x 11^{2} = 2^{22} x 7^{5} x11^{2}
Total number of prime factors = (22 + 5 + 2) = 29.
Incorrect
(4)^{11}x (7)^{5} x (11)^{2} = (2 x 2)^{11} x (7)^{5} x (11)^{2} = 2^{11} x 2^{11} x7^{5}x 11^{2} = 2^{22} x 7^{5} x11^{2}
Total number of prime factors = (22 + 5 + 2) = 29.

Question 17 of 20
17. Question
Which digits should come in place of * and $ if the number 62684*$ is divisible by both 8 and 5 ?
Correct
Since the given number is divisible by 5, so 0 or 5 must come in place of $. But, a number ending with 5 is never divisible by 8. So, 0 will replace $.
Now, the number formed by the last three digits is 4*0, which becomes divisible by 8, if * is replaced by 4.
Hence, digits in place of * and $ are 4 and 0 respectively.
Incorrect
Since the given number is divisible by 5, so 0 or 5 must come in place of $. But, a number ending with 5 is never divisible by 8. So, 0 will replace $.
Now, the number formed by the last three digits is 4*0, which becomes divisible by 8, if * is replaced by 4.
Hence, digits in place of * and $ are 4 and 0 respectively.

Question 18 of 20
18. Question
Show that 4832718 is divisible by 11.
Correct
(Sum of digits at odd places) – (Sum of digits at even places)
= (8 + 7 + 3 + 4) – (1 + 2 + 8) = 11, which is divisible by 11.
Hence, 4832718 is divisible by 11.
Incorrect
(Sum of digits at odd places) – (Sum of digits at even places)
= (8 + 7 + 3 + 4) – (1 + 2 + 8) = 11, which is divisible by 11.
Hence, 4832718 is divisible by 11.

Question 19 of 20
19. Question
What least number must be added to 3000 to obtain a number exactly divisible by 19 ?
Correct
On dividing 3000 by 19, we get 17 as remainder.
Number to be added = (19 – 17) = 2.
Incorrect
On dividing 3000 by 19, we get 17 as remainder.
Number to be added = (19 – 17) = 2.

Question 20 of 20
20. Question
Find the number which is nearest to 3105 and is exactly divisible by 21.
Correct
On dividing 3105 by 21, we get 18 as remainder.
Number to be added to 3105 = (21 – 18) – 3.
Hence, required number = 3105 + 3 = 3108.
Incorrect
On dividing 3105 by 21, we get 18 as remainder.
Number to be added to 3105 = (21 – 18) – 3.
Hence, required number = 3105 + 3 = 3108.