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Number of Questions: 10
Time: 10 Minutes
Category: Aptitude
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Question 1 of 30
1. Question
man buys an article for Rs. 27.50 and sells it for Rs 28.60. Find his gain percent
Correct
Answer: Option D
Explanation:
So we have C.P. = 27.50
S.P. = 28.60Gain = 28.60 – 27.50 = Rs. 1.10
Gain%=(Gain/Cost∗100)%=(1.10/27.50∗100)%=4%
Incorrect
Answer: Option D
Explanation:
So we have C.P. = 27.50
S.P. = 28.60Gain = 28.60 – 27.50 = Rs. 1.10
Gain%=(Gain/Cost∗100)%=(1.10/27.50∗100)%=4%

Question 2 of 30
2. Question
A person incurs a loss of 5% be selling a watch for Rs. 1140. At what price should the watch be sold to earn 5% profit
Correct
Answer: Option C
Explanation:
Let the new S.P. be x, then.
(100 – loss%):(1st S.P.) = (100 + gain%):(2nd S.P.)=(95/1140=105/x)
=x=1260Incorrect
Answer: Option C
Explanation:
Let the new S.P. be x, then.
(100 – loss%):(1st S.P.) = (100 + gain%):(2nd S.P.)=(95/1140=105/x)
=x=1260 
Question 3 of 30
3. Question
If the cost price is 25% of selling price. Then what is the profit percent.
Correct
Answer: Option C
Explanation:
Let the S.P = 100
then C.P. = 25Profit = 75
Profit% = 75/25 * 100 = 3005
Incorrect
Answer: Option C
Explanation:
Let the S.P = 100
then C.P. = 25Profit = 75
Profit% = 75/25 * 100 = 3005

Question 4 of 30
4. Question
The cash difference between the selling prices of an article at a profit of 4% and 6% is Rs 3. The ratio of two selling prices is
Correct
Answer: Option B
Explanation:
Let the Cost price of article is Rs. xRequired ratio =
104% of x/106% of x=104/106=52/53=52:53Incorrect
Answer: Option B
Explanation:
Let the Cost price of article is Rs. xRequired ratio =
104% of x/106% of x=104/106=52/53=52:53 
Question 5 of 30
5. Question
If selling price is doubled, the profit triples. Find the profit percent.
Correct
Answer: Option B
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y – x) = (2y – x) = y = 2x.
Profit = Rs. (y – x) = Rs. (2x – x) = Rs. x.
Profit % =(x/x x 100)% = 100%
Incorrect
Answer: Option B
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y – x) = (2y – x) = y = 2x.
Profit = Rs. (y – x) = Rs. (2x – x) = Rs. x.
Profit % =(x/x x 100)% = 100%

Question 6 of 30
6. Question
A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Rs. 392, what was his profit?
Correct
Answer: Option C
Explanation:
C.P.=Rs.(
Rs.=Rs.320Profit = Rs. (392 – 320) = Rs. 72.
Incorrect
Answer: Option C
Explanation:
C.P.=Rs.(
Rs.=Rs.320Profit = Rs. (392 – 320) = Rs. 72.

Question 7 of 30
7. Question
The cost price of a particular amount of articles is same as the number of articles. Selling price of the articles comes out to be 20. Over the whole transaction 25% is gained. What is X?
Correct
ANSWER: C
Explanation:
According to the question let n be the number of articles.Cost price of n articles = n
Selling price of n articles = 20
Profit % = 25%
Profit % = (SP – CP)/CP X 100
Putting the values in the formula
(20n)/n x 100 = 25
5n/4 = 20
n = 16
Incorrect
ANSWER: C
Explanation:
According to the question let n be the number of articles.Cost price of n articles = n
Selling price of n articles = 20
Profit % = 25%
Profit % = (SP – CP)/CP X 100
Putting the values in the formula
(20n)/n x 100 = 25
5n/4 = 20
n = 16

Question 8 of 30
8. Question
A shopkeeper sells his goods at cost price but uses a faulty meter that weighs 950 grams. Find the profit percent
Correct
ANSWER: C
Explanation:
(100 + g) / (100 + x) = True measure / Faulty measurex = 0
true measure = 1000
faulty measure = 950
100 + g / 100 + 0 = 1000 / 950
100+g = 20/19*100
g = 100/19 %Incorrect
ANSWER: C
Explanation:
(100 + g) / (100 + x) = True measure / Faulty measurex = 0
true measure = 1000
faulty measure = 950
100 + g / 100 + 0 = 1000 / 950
100+g = 20/19*100
g = 100/19 % 
Question 9 of 30
9. Question
What is the CP of Rs 100 stock at 4 discount, with 1/5% brokerage?
Correct
ANSWER: B
Explanation:
Use the formula,
CP= 100 – discount + brokerage%
CP= 1004+1/5
96.2Thus the CP is Rs 96.2
Incorrect
ANSWER: B
Explanation:
Use the formula,
CP= 100 – discount + brokerage%
CP= 1004+1/5
96.2Thus the CP is Rs 96.2

Question 10 of 30
10. Question
P, Q, R subscribe Rs. 50,000 for a business. P subscribes Rs. 4000 more than Q and Q Rs. 5000 more than R. Out of a total profit of Rs. 25,000, what will be P’s share?
Correct
ANSWER: B
Explanation:
Let amount subscribed for R be x.
Therefore, Q = x + 5000 and P = x + 5000 + 4000 = x + 9000
So, x + x + 5000 + x + 9000 = 50000
3x = 36000
x = 12000
P : Q : R = 21000 : 17000 : 12000 = 21 : 17 : 12
P’s share = 25000 X (21/50) = Rs. 10,500.Incorrect
ANSWER: B
Explanation:
Let amount subscribed for R be x.
Therefore, Q = x + 5000 and P = x + 5000 + 4000 = x + 9000
So, x + x + 5000 + x + 9000 = 50000
3x = 36000
x = 12000
P : Q : R = 21000 : 17000 : 12000 = 21 : 17 : 12
P’s share = 25000 X (21/50) = Rs. 10,500. 
Question 11 of 30
11. Question
A man buys an article for rs.27.50 and sells it for rs.28.50. find his gain %.
Correct
cp=rs27.50, sp=rs 28.50
gain=rs(28.50 –27.50)=rs1.10
so gain%={(1.10/27.50)*100}=4%
Incorrect
cp=rs27.50, sp=rs 28.50
gain=rs(28.50 –27.50)=rs1.10
so gain%={(1.10/27.50)*100}=4%

Question 12 of 30
12. Question
If the a radio is sold for rs 490 and sold for rs 465.50.find loss%.
Correct
cp=rs490,sp= 465.50.
loss=rs(490465.50)=rs 24.50.
loss%=[(24.50/490)*100]%=5%
Incorrect
cp=rs490,sp= 465.50.
loss=rs(490465.50)=rs 24.50.
loss%=[(24.50/490)*100]%=5%

Question 13 of 30
13. Question
A person incurs loss for by selling a watch for rs 1140.at what price should the watch be sold to earn a 5% profit ?
Correct
let the new SP be Rs x.then
(100loss%) : (1^{st} sp)=(100+gain%) (2^{nd} sp)
{(1005)/1400}={(100+5)/x}=> x={(105*1140)/95} =1260.
Incorrect
let the new SP be Rs x.then
(100loss%) : (1^{st} sp)=(100+gain%) (2^{nd} sp)
{(1005)/1400}={(100+5)/x}=> x={(105*1140)/95} =1260.

Question 14 of 30
14. Question
By selling 33 metres of cloth , one gains the selling price of 11 metres . Find the gain percent .
Correct
(SP of 33m)(CP of 33m)=Gain=SP of 11m
SP of 22m = CP of 33m
Let CP of each metre be Re.1 , Then, CP of 22m= Rs.22,SP of 22m=Rs.33.
Gain%=[(11/22)*100]%=50%
Incorrect
(SP of 33m)(CP of 33m)=Gain=SP of 11m
SP of 22m = CP of 33m
Let CP of each metre be Re.1 , Then, CP of 22m= Rs.22,SP of 22m=Rs.33.
Gain%=[(11/22)*100]%=50%

Question 15 of 30
15. Question
A vendor bought bananas at 6 for Rs.10 and sold them at Rs.4 for Rs.6 .Find his gain or loss percent
Correct
Suppose , number of bananas bought = LCM of 6 and 4=12
CP=Rs.[(10/6)*12]=Rs.20 ; SP= Rs[(6/4)*12]=Rs.18
Loss%=[(2/20)*100]%=10%
Incorrect
Suppose , number of bananas bought = LCM of 6 and 4=12
CP=Rs.[(10/6)*12]=Rs.20 ; SP= Rs[(6/4)*12]=Rs.18
Loss%=[(2/20)*100]%=10%

Question 16 of 30
16. Question
A man brought toffees at for a rupee. How many for a rupee must he sell to gain 50%?
Correct
C.P of 3 toffees=Re 1; S.P of 3 toffees =150% of Re.1=3/2.
For Rs.3/2, toffees sold =3, for Re.1, toffees sold = [3*(2/3)] = 2.
Incorrect
C.P of 3 toffees=Re 1; S.P of 3 toffees =150% of Re.1=3/2.
For Rs.3/2, toffees sold =3, for Re.1, toffees sold = [3*(2/3)] = 2.

Question 17 of 30
17. Question
A grocer purchased 80 kg of sugar at Rs.13.50 per kg and mixed it with 120kg sugar at Rs.16per kg. At what rate should he sell the mixer to gain 16%?
Correct
C.P of 200 kg of mixture = Rs. (80 * 13.50+120*16) = Rs.3000.
S.P =116% 0f Rs.3000 =Rs.[(116/200) *3000]=Rs.3480.
\ Rate of S.P of the mixture =Rs.[3480/200] per kg =Rs.17.40 per kg.
Incorrect
C.P of 200 kg of mixture = Rs. (80 * 13.50+120*16) = Rs.3000.
S.P =116% 0f Rs.3000 =Rs.[(116/200) *3000]=Rs.3480.
\ Rate of S.P of the mixture =Rs.[3480/200] per kg =Rs.17.40 per kg.

Question 18 of 30
18. Question
Pure ghee cost Rs.100 per kg. After adulterating it with vegetable oil costing Rs.50 per kg, A shopkeeper sells the mixture at the rate of Rs.96 per kg, thereby making a profit of 20%.In What ratio does he mix the two?
Correct
Mean cost price =Rs. [ (100/120)*96 ] =Rs.80 per kg.
Incorrect
Mean cost price =Rs. [ (100/120)*96 ] =Rs.80 per kg.

Question 19 of 30
19. Question
A dishonest dealer professes to sell his goods at cost price but uses a weight of 960 gms for a kg weight . Find his gain percent.
Correct
Gain% =( Error )/ (error value)(error) *100 ]% = [(40/960)*100] % = 25/6 %
Incorrect
Gain% =( Error )/ (error value)(error) *100 ]% = [(40/960)*100] % = 25/6 %

Question 20 of 30
20. Question
If the manufacturer gains 10%,the wholesale dealer 15% and the retailer 25% ,then find the cost of production of a ,the retail price of which is Rs.1265?
Correct
Let the cost of production of the table be Rs x
The ,125% of 115% of 110% of x=1265
125/100*115/100*110/100*x=1265=>253/160*x=>1265=>x=(1265*160/253)=Rs.800
Incorrect
Let the cost of production of the table be Rs x
The ,125% of 115% of 110% of x=1265
125/100*115/100*110/100*x=1265=>253/160*x=>1265=>x=(1265*160/253)=Rs.800

Question 21 of 30
21. Question
Monika purchesed a pressure cooker at 9/10^{th }of its selling price and sold it at 8% more than its S.P .find her gain percent.
Correct
Let the s.p be Rs. X .then C.P = Rs.9x/10,Receipt=108% of rs.x=Rs 27x/25
Gain=Rs (27x/25*9x/10)=Rs(108x90x/100)=Rs18x/100
Gain%=(18x/100*10/9x*100)%=20%
Incorrect
Let the s.p be Rs. X .then C.P = Rs.9x/10,Receipt=108% of rs.x=Rs 27x/25
Gain=Rs (27x/25*9x/10)=Rs(108x90x/100)=Rs18x/100
Gain%=(18x/100*10/9x*100)%=20%

Question 22 of 30
22. Question
An article is sold at certain price. By selling it at 2/3 of its price one losses 10%,find the gain at original price ?
Correct
let the original s.p be Rs x. then now S.P=Rs2x/3,loss=10%
now C.P=Rs20x/27*27/20x*100)%=35%
Incorrect
let the original s.p be Rs x. then now S.P=Rs2x/3,loss=10%
now C.P=Rs20x/27*27/20x*100)%=35%

Question 23 of 30
23. Question
A tradesman sold an article at a loss of 20%.if the selling price has been increased by Rs100,ther would have been a gain of 5%.what was the cost price of the article?
Correct
Let C.P be Rs x. then (105% of x)(80 % of x)=100 or 25% of x=100
 x/4=100 or x=400
 so,C.P =Rs 400
Incorrect
Let C.P be Rs x. then (105% of x)(80 % of x)=100 or 25% of x=100
 x/4=100 or x=400
 so,C.P =Rs 400

Question 24 of 30
24. Question
. A man sells an article at a profit of 25%if he had bought it 20% less and sold it for Rs 10.50 less,he would have gained 30%find the cost price of the article.
Correct
Let the C.P be Rs x
1^{st} S.P=125% of x =125x/100=5x/4;2^{nd} S.P=80% of x=80x/100=4x/5
2^{nd} S.P=130% of 4x/5=(130/100*4x/5)=26x/25
=>5x/426x/25=10.50óx=(10.50*100)/21=50
hence C.P=Rs.50
Incorrect
Let the C.P be Rs x
1^{st} S.P=125% of x =125x/100=5x/4;2^{nd} S.P=80% of x=80x/100=4x/5
2^{nd} S.P=130% of 4x/5=(130/100*4x/5)=26x/25
=>5x/426x/25=10.50óx=(10.50*100)/21=50
hence C.P=Rs.50

Question 25 of 30
25. Question
The price of the jewel,passing through three hands,rises on the whole by65%.if the first and the second sellers 20%and25% profit respectively find the percentage profit earned by the third seller.
Correct
Let the orginal price of the jewel be Rs p and let the profit earned by the thrid seller be x%
Then,(100+x)% of 125% OF 120% OF P=165% OF P
 ((100+X)/100*125/100*120/100*P)=(165/100*P)
 (100+X)=(165*100*100)/(125*120)=110=>X=10%
Incorrect
Let the orginal price of the jewel be Rs p and let the profit earned by the thrid seller be x%
Then,(100+x)% of 125% OF 120% OF P=165% OF P
 ((100+X)/100*125/100*120/100*P)=(165/100*P)
 (100+X)=(165*100*100)/(125*120)=110=>X=10%

Question 26 of 30
26. Question
A man 2 flats for Rs 675958 each.on one he gains 16% while on the other he losses 16%. How much does he gain/loss in the whole transaction?
Correct
In this case there will be alwalys loss. The selling price is immaterial
Hence, loss % = (common loss and gain%)^{2 }/10=(16/10)%=(64/25)%=2.56%
Incorrect
In this case there will be alwalys loss. The selling price is immaterial
Hence, loss % = (common loss and gain%)^{2 }/10=(16/10)%=(64/25)%=2.56%

Question 27 of 30
27. Question
A dealer sold threefourth of his article at a gain of 20% and remaining at a cost price. Find the gain earned by him at the two transaction.
Correct
Let the C.P of the whole be Rs x
C.P of 3/4^{th} =Rs 3x/4,C.P of 1/4^{th} =Rs x/4
 total S.P=Rs [(120%of 3x/4)+x/4]=Rs(9x/10+x/4)=Rs 23x/20
 gain=Rs(23x/20x)=Rs 3x/20
 gain%=3x/20*1/x*100)%=15%
Incorrect
Let the C.P of the whole be Rs x
C.P of 3/4^{th} =Rs 3x/4,C.P of 1/4^{th} =Rs x/4
 total S.P=Rs [(120%of 3x/4)+x/4]=Rs(9x/10+x/4)=Rs 23x/20
 gain=Rs(23x/20x)=Rs 3x/20
 gain%=3x/20*1/x*100)%=15%

Question 28 of 30
28. Question
A man bought a horse and a car riage for Rs 3000.he sold the horse at a gain of 20% and the carriage at a loss of 10%,thereby gaining 2% on the whole.find the cost of the horse.
Correct
Let the C.p of the horse be Rs.x, then C.P of the carriage =Rs(3000x)
20% of x10% of(3000x)=2% of 3000
 x/5(3000x)/10=60=.2x3000+x=600=.3x+3600=>x=1200
 hence,C.P of the horse =Rs 1200
Incorrect
Let the C.p of the horse be Rs.x, then C.P of the carriage =Rs(3000x)
20% of x10% of(3000x)=2% of 3000
 x/5(3000x)/10=60=.2x3000+x=600=.3x+3600=>x=1200
 hence,C.P of the horse =Rs 1200

Question 29 of 30
29. Question
find the single discount equivalent to a series discount of 20% ,10% and 5%
Correct
let the marked price be Rs 100
then ,net S.P=95% of 90% of 80% of Rs 100
=Rs(95/100*90/100*80/100*100)=Rs68.40
Incorrect
let the marked price be Rs 100
then ,net S.P=95% of 90% of 80% of Rs 100
=Rs(95/100*90/100*80/100*100)=Rs68.40

Question 30 of 30
30. Question
After getting 2 successive discounts, a shirt with a list price of Rs 150 is available at Rs 105. If the second discount is 12.55,find the first discount.
Correct
Let the first discount be x%
Then,87.5% of (100x)% of 150= 105
 5/100*(100x)/100*450=150=>105=>100x=(105*100*100)/(150*87.5)=80
 x=(10080)=20
 first discount = 20%
Incorrect
Let the first discount be x%
Then,87.5% of (100x)% of 150= 105
 5/100*(100x)/100*450=150=>105=>100x=(105*100*100)/(150*87.5)=80
 x=(10080)=20
 first discount = 20%