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Number of Questions: 20
Time: 20 Minutes
Category: Aptitude
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Question 1 of 20
1. Question
A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
Correct
Answer: Option B
Explanation:
Speed =( ) = 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
=(2* )
= 7.2 km/hr.Incorrect
Answer: Option B
Explanation:
Speed =( ) = 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
=(2* )
= 7.2 km/hr. 
Question 2 of 20
2. Question
A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
Correct
Answer: Option B
Explanation:
=10
=20
15x = 168 x 20x==224 km
Incorrect
Answer: Option B
Explanation:
=10
=20
15x = 168 x 20x==224 km

Question 3 of 20
3. Question
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Correct
Solution:
Option(D) is correctDue to stoppages, it covers 9 km less.
Time taken to cover 9 km = 9/54×60 = 10 min.
Incorrect
Solution:
Option(D) is correctDue to stoppages, it covers 9 km less.
Time taken to cover 9 km = 9/54×60 = 10 min.

Question 4 of 20
4. Question
How many minutes does Aditya take to cover a distance of 400 m, if he runs at a speed of 20 km/h
Correct
Answer: Option A
Explanation:
We know that,
Time=Distance/Speed
Speed=20 km/hr=20∗5/18m/sec
=50/9m/sec
Time =(400∗9/50)=
72sec=1.2minIncorrect
Answer: Option A
Explanation:
We know that,
Time=Distance/Speed
Speed=20 km/hr=20∗5/18m/sec
=50/9m/sec
Time =(400∗9/50)=
72sec=1.2min 
Question 5 of 20
5. Question
A train covers a distance in 50 minutes, if it runs at a speed of 48kmph on an average. Find the speed at which the train must run to reduce the time of journey to 40 minutes.
Correct
Answer: Option B
Explanation:
We are having time and speed given, so first we will calculate the distance. Then we can get new speed for given time and distance.
Lets solve it.Time = 50/60 hr = 5/6 hr
Speed = 48 mph
Distance = S*T = 48 * 5/6 = 40 kmNew time will be 40 minutes so,
Time = 40/60 hr = 2/3 hr
Now we know,
Speed = Distance/Time
New speed = 40*3/2 kmph = 60kmphIncorrect
Answer: Option B
Explanation:
We are having time and speed given, so first we will calculate the distance. Then we can get new speed for given time and distance.
Lets solve it.Time = 50/60 hr = 5/6 hr
Speed = 48 mph
Distance = S*T = 48 * 5/6 = 40 kmNew time will be 40 minutes so,
Time = 40/60 hr = 2/3 hr
Now we know,
Speed = Distance/Time
New speed = 40*3/2 kmph = 60kmph 
Question 6 of 20
6. Question
Two boys starting from the same place walk at a rate of 5kmph and 5.5kmph respectively. What time will they take to be 8.5km apart, if they walk in the same direction?
Correct
Answer: Option C
Explanation:
In this type of questions we need to get the relative speed between them,
The relative speed of the boys = 5.5kmph – 5kmph
= 0.5 kmphDistance between them is 8.5 km
Time = Distance/Speed
Time= 8.5km / 0.5 kmph = 17 hrsIncorrect
Answer: Option C
Explanation:
In this type of questions we need to get the relative speed between them,
The relative speed of the boys = 5.5kmph – 5kmph
= 0.5 kmphDistance between them is 8.5 km
Time = Distance/Speed
Time= 8.5km / 0.5 kmph = 17 hrs 
Question 7 of 20
7. Question
2 trains starting at the same time from 2 stations 200 km apart and going in opposite direction cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds ?
Correct
Answer: Option A
Explanation:
We know total distance is 200 Km
If both trains crossed each other at a distance of 110 km then one train covered 110 km and other 90 km [110+90=200km]
So ratio of their speed = 110:90 = 11:9Incorrect
Answer: Option A
Explanation:
We know total distance is 200 Km
If both trains crossed each other at a distance of 110 km then one train covered 110 km and other 90 km [110+90=200km]
So ratio of their speed = 110:90 = 11:9 
Question 8 of 20
8. Question
A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. Find the average speed for first 320 km of tour.
Correct
Answer: Option B
Explanation:
We know Time = Distance/speedSo total time taken =
(160/64+160/80)=9/2hours
Time taken for 320 Km = 320∗2/9=71.11km/hrIncorrect
Answer: Option B
Explanation:
We know Time = Distance/speedSo total time taken =
(160/64+160/80)=9/2hours
Time taken for 320 Km = 320∗2/9=71.11km/hr 
Question 9 of 20
9. Question
The ratio between the speeds of two trains is 7: 8. If the second train runs 400 kms in 4 hours, then the speed of the first train is ?
Correct
Answer: Option D
Explanation:
Let the speeds of two trains be 7X and 8X km/hr.8X=400/4
X=12.5 Km/hr
So speed of first train is 12.5*7 = 87.5 km/hrIncorrect
Answer: Option D
Explanation:
Let the speeds of two trains be 7X and 8X km/hr.8X=400/4
X=12.5 Km/hr
So speed of first train is 12.5*7 = 87.5 km/hr 
Question 10 of 20
10. Question
Ram and Sham are running a race, Ram runs 25% faster than Sham and is able to allow Sham a lead of 7 meters to end a race in dead heat. Find the distance of the race.
Correct
Answer: Option B
Explanation:
Important to Note first – Dead Head means – run or finish a race at exactly level or at same time.From question it is clear that Ram runs faster than Sham by 25%,
So if Sham runs 100 meter in a given time then Ram will run 125 meter in that time.
So if Sham runs 4 meter then Ram will run 5 meter in given time (divide both by 25)
=> Ram can give Sham a lead of 1 meter in 5 meter race to finish race in dead heat.
Ratio of length of start given : length of race :: 1 : 5
As per question, start was given of 7 meter, So,
Length of race was 7 * 5 = 35.Incorrect
Answer: Option B
Explanation:
Important to Note first – Dead Head means – run or finish a race at exactly level or at same time.From question it is clear that Ram runs faster than Sham by 25%,
So if Sham runs 100 meter in a given time then Ram will run 125 meter in that time.
So if Sham runs 4 meter then Ram will run 5 meter in given time (divide both by 25)
=> Ram can give Sham a lead of 1 meter in 5 meter race to finish race in dead heat.
Ratio of length of start given : length of race :: 1 : 5
As per question, start was given of 7 meter, So,
Length of race was 7 * 5 = 35. 
Question 11 of 20
11. Question
P beats Q by 5 seconds in a race of 1000 m and Q beats R by 5 metres in a race of 100 m. By how many seconds does P beats R in a race of 1000 m?
Correct
If P takes tt seconds to run 1000 m, then Q takes (t+5)(t+5) sec.
In (t+5)(t+5) sec Q runs 100 m whereas R runs only 950 m.
RR runs 1000 m in 1000950×(t+5)1000950×(t+5)sec
P takes t seconds to cover 1000m , while R takes (20t/19+100/95)(20t/19+100/95)sec
From the data given, we cannot determine t
Incorrect
If P takes tt seconds to run 1000 m, then Q takes (t+5)(t+5) sec.
In (t+5)(t+5) sec Q runs 100 m whereas R runs only 950 m.
RR runs 1000 m in 1000950×(t+5)1000950×(t+5)sec
P takes t seconds to cover 1000m , while R takes (20t/19+100/95)(20t/19+100/95)sec
From the data given, we cannot determine t

Question 12 of 20
12. Question
Starting from my office, I reach the house 20 min late if I walk at 3kmph. Instead, if I walk at 4 kmph, I reach the house 15 min early. How far is my house from my office?
Correct
Let the distance between the office and the house be 1 km
Time required at 3 kmph
=1/3=20min
Time required at 4 kmph
=1/4=15min
Difference = 20−15=5 min.
Actual difference in timings = 20+15=35 min
If difference is 5 min, distance is 1 km
⇒⇒ If difference is 35 min, distance is 7 km
Incorrect
Let the distance between the office and the house be 1 km
Time required at 3 kmph
=1/3=20min
Time required at 4 kmph
=1/4=15min
Difference = 20−15=5 min.
Actual difference in timings = 20+15=35 min
If difference is 5 min, distance is 1 km
⇒⇒ If difference is 35 min, distance is 7 km

Question 13 of 20
13. Question
A car covers a distance of 816 kms in 12 hours. What is the speed of the car ?
Correct
Speed of the car = Distance covered/Time Taken = 816/ 12 = 68 kmph.
Incorrect
Speed of the car = Distance covered/Time Taken = 816/ 12 = 68 kmph.

Question 14 of 20
14. Question
The driver of a car driving @ 36 kmph locates a bus 40 meters ahead of him. After 20 seconds the bus is 60 meters behind. The speed of the bus is :
Correct
Net distance gained by car over the bus = 40 + 60 = 100m, in 20 sec.
Time = Distance /Relative speed
20=100/(36*5/18)S
S=5 m/s= 18 kmph
Incorrect
Net distance gained by car over the bus = 40 + 60 = 100m, in 20 sec.
Time = Distance /Relative speed
20=100/(36*5/18)S
S=5 m/s= 18 kmph

Question 15 of 20
15. Question
A train covers a distance in 50 min ,if it runs at a speed of 48kmph on an average.The speed at which the train must run to reduce the time of journey to 40 min will be.
Correct
Time=50/60 hr=5/6hr
Speed=48mph d
istance=S*T=48*5/6=40km
time=40/60hr=2/3hr
New speed = 40* 3/2 kmph= 60kmph
Incorrect
Time=50/60 hr=5/6hr
Speed=48mph d
istance=S*T=48*5/6=40km
time=40/60hr=2/3hr
New speed = 40* 3/2 kmph= 60kmph

Question 16 of 20
16. Question
A train traveling at 72 kmph crosses a platform in 30 seconds and a man standing on the platform in 18 seconds. What is the length of the platform in meters?
Correct
Length of the platform = speed of train * extra time taken to cross the platform.
Length of platform = 72 kmph * 12 secondsConvert 72 kmph into m/sec
1 kmph = 5/18 m/s (This can be easily derived. But if you can remember this conversion, it saves a good 30 seconds).
∴ 72 kmph = 5/18∗72= 20 m/secTherefore, length of the platform = 20 m/s * 12 sec = 240 meters.
Incorrect
Length of the platform = speed of train * extra time taken to cross the platform.
Length of platform = 72 kmph * 12 secondsConvert 72 kmph into m/sec
1 kmph = 5/18 m/s (This can be easily derived. But if you can remember this conversion, it saves a good 30 seconds).
∴ 72 kmph = 5/18∗72= 20 m/secTherefore, length of the platform = 20 m/s * 12 sec = 240 meters.

Question 17 of 20
17. Question
Steve traveled the first 2 hours of his journey at 40 mph and the remaining 3 hours of his journey at 80 mph. What is his average speed for the entire journey?
Correct
Average speed of travel = Total distance travelledTotal time takenTotal distance travelledTotal time taken
Total distance traveled by Steve = Distance covered in the first 2 hours + distance covered in the next 3 hours.
Distance covered in the first 2 hours = speed * time = 40 * 2 = 80 miles.
Distance covered in the next 3 hours = speed * time = 80 * 3 = 240 miles.
Therefore, total distance covered = 80 + 240 = 320 miles.Total time taken = 2 + 3 = 5 hours.
Hence, average speed = Total distance travelled
Total time taken=320/5
Total distance travelled
Total time taken=320/5 = 64 miles per hour.
Incorrect
Average speed of travel = Total distance travelledTotal time takenTotal distance travelledTotal time taken
Total distance traveled by Steve = Distance covered in the first 2 hours + distance covered in the next 3 hours.
Distance covered in the first 2 hours = speed * time = 40 * 2 = 80 miles.
Distance covered in the next 3 hours = speed * time = 80 * 3 = 240 miles.
Therefore, total distance covered = 80 + 240 = 320 miles.Total time taken = 2 + 3 = 5 hours.
Hence, average speed = Total distance travelled
Total time taken=320/5
Total distance travelled
Total time taken=320/5 = 64 miles per hour.

Question 18 of 20
18. Question
Walking at the rate of 4 kmph a man cover certain distance in 2 hr 45 min. Running at a speed of 16.5 kmph the man will cover the same distance in.
Correct
Distance = Speed × time
Here time = 2hr 45 min = 11/4 hr
Distance = 4×11/4=11 km
New Speed =16.5 kmph
Therefore time = DS=11/16.5=40 min
Incorrect
Distance = Speed × time
Here time = 2hr 45 min = 11/4 hr
Distance = 4×11/4=11 km
New Speed =16.5 kmph
Therefore time = DS=11/16.5=40 min

Question 19 of 20
19. Question
A train traveling at 100 kmph overtakes a motorbike traveling at 64 kmph in 40 seconds. What is the length of the train in meters?
Correct
When a train overtakes another object such as a motorbike, whose length is negligible compared to the length of the train, then the distance travelled by the train while overtaking the motorbike is the same as the length of the train.
The length of the train:
= distance travelled by the train while overtaking the motorbike
= relative speed between the train and the motorbike × time taken
In this case, as both the objects i.e., the train and the motorbike are moving in the same direction, the relative speed between them = difference between their respective speeds = 100−64=36 kmph
Distance travelled by the train while overtaking the motorbike
=36 kmph ×40 seconds.
The final answer is given in meters and the speed is given in kmph and the time in seconds.
So let us convert the given speed from kmph to m/sec.
1 kmph = 5/18 m/sec
Therefore, 36 kmph = 36×5/18=10m/sec
Relative speed = 10 m/sec.
Time taken = 40 seconds.
Therefore, distance travelled =10×4010×40= 400 meters
Incorrect
When a train overtakes another object such as a motorbike, whose length is negligible compared to the length of the train, then the distance travelled by the train while overtaking the motorbike is the same as the length of the train.
The length of the train:
= distance travelled by the train while overtaking the motorbike
= relative speed between the train and the motorbike × time taken
In this case, as both the objects i.e., the train and the motorbike are moving in the same direction, the relative speed between them = difference between their respective speeds = 100−64=36 kmph
Distance travelled by the train while overtaking the motorbike
=36 kmph ×40 seconds.
The final answer is given in meters and the speed is given in kmph and the time in seconds.
So let us convert the given speed from kmph to m/sec.
1 kmph = 5/18 m/sec
Therefore, 36 kmph = 36×5/18=10m/sec
Relative speed = 10 m/sec.
Time taken = 40 seconds.
Therefore, distance travelled =10×4010×40= 400 meters

Question 20 of 20
20. Question
Ram covers a part of the journey at 20 kmph and the balance at 70 kmph taking total of 8 hours to cover the distance of 400 km. How many hours has he been driving at 20 kmph?
Correct
Let xx be the number of hours he travels at 20 kmph.
Distance covered in this x hours = 20x km
He would have therefore, travelled the balance (8–x) hours at 70 kmph.
Distance covered in this 8–x hours = (8−x)×70=(560–70x) km
The total distance travelled = 20x+560–70x=400
⇒160=50x
x=(16050) hours
= 3.2 hours
= 3 hours and 12 minutes
Incorrect
Let xx be the number of hours he travels at 20 kmph.
Distance covered in this x hours = 20x km
He would have therefore, travelled the balance (8–x) hours at 70 kmph.
Distance covered in this 8–x hours = (8−x)×70=(560–70x) km
The total distance travelled = 20x+560–70x=400
⇒160=50x
x=(16050) hours
= 3.2 hours
= 3 hours and 12 minutes