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Number of Questions: 10
Time: 10 Minutes
Category: Aptitude
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Question 1 of 30
1. Question
A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?
Correct
Let the length of the train be x metres and its speed by y m/sec.
Then, = 8 => x = 8y
Now, = y
=> 8y + 264 = 20y=> y = 22.
Therefore Speed = 22 m/sec = 22 *= 79.2km/hr
Incorrect
Let the length of the train be x metres and its speed by y m/sec.
Then, = 8 => x = 8y
Now, = y
=> 8y + 264 = 20y=> y = 22.
Therefore Speed = 22 m/sec = 22 *= 79.2km/hr

Question 2 of 30
2. Question
How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Correct
Speed of the train relative to man = (63 – 3) km/hr = 60 km/hr
= (60 x )m/sec
= ( )m/sec.Therefore Time taken to pass the man
= ( 500 x ) sec
= 30 sec.Incorrect
Speed of the train relative to man = (63 – 3) km/hr = 60 km/hr
= (60 x )m/sec
= ( )m/sec.Therefore Time taken to pass the man
= ( 500 x ) sec
= 30 sec. 
Question 3 of 30
3. Question
Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
Correct
Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x – 1) hours = 25(x – 1) km.
20x + 25(x – 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.
Incorrect
Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x – 1) hours = 25(x – 1) km.
20x + 25(x – 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.

Question 4 of 30
4. Question
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Correct
Speed of train relative to jogger = (45 – 9) km/hr = 36 km/hr.
=36 x m/sec
= 10 m/sec.Distance to be covered = (240 + 120) m = 360 m.
Time taken =sec= 36 sec
Incorrect
Speed of train relative to jogger = (45 – 9) km/hr = 36 km/hr.
=36 x m/sec
= 10 m/sec.Distance to be covered = (240 + 120) m = 360 m.
Time taken =sec= 36 sec

Question 5 of 30
5. Question
A train, 800 meter long is running with a speed of 78 km/hr. It crosses a tunnel in 1 minute. What is the length of the tunnel ?
Correct
Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 secondsSpeed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
=>800+x=65/3*60
=>800+x=20*65=1300
=>x=1300−800=500So the length of the tunnel is 500 meters.
Incorrect
Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 secondsSpeed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
=>800+x=65/3*60
=>800+x=20*65=1300
=>x=1300−800=500So the length of the tunnel is 500 meters.

Question 6 of 30
6. Question
A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is:
Correct
Let the speed of the stream be x km/hr. Then,
Speed downstream = (15 + x) km/hr,
Speed upstream = (15 – x) km/hr.
= + =4
= =
9 = 225= 25
x = 5 km/hr.
Incorrect
Let the speed of the stream be x km/hr. Then,
Speed downstream = (15 + x) km/hr,
Speed upstream = (15 – x) km/hr.
= + =4
= =
9 = 225= 25
x = 5 km/hr.

Question 7 of 30
7. Question
A man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place?
Correct
Speed downstream = (5 + 1) kmph = 6 kmph.
Speed upstream = (5 – 1) kmph = 4 kmph.
Let the required distance be x km.
Then, + =1
2x + 3x = 125x = 12
x = 2.4 km.
Incorrect
Speed downstream = (5 + 1) kmph = 6 kmph.
Speed upstream = (5 – 1) kmph = 4 kmph.
Let the required distance be x km.
Then, + =1
2x + 3x = 125x = 12
x = 2.4 km.

Question 8 of 30
8. Question
A man takes twice as long to row a distance against the stream as to row the same distance in favour of the stream. The ratio of the speed of the boat (in still water) and the stream is:
Correct
Let man’s rate upstream be x kmph.
Then, his rate downstream = 2x kmph.
(Speed in still water) : (Speed of stream) = :
= :
= 3 : 1.Incorrect
Let man’s rate upstream be x kmph.
Then, his rate downstream = 2x kmph.
(Speed in still water) : (Speed of stream) = :
= :
= 3 : 1. 
Question 9 of 30
9. Question
A man rows 750 m in 675 seconds against the stream and returns in 7 and half minutes. His rowing speed in still water is
Correct
Rate upstream = (750/675) = 10/9 m/sec
Rate downstream (750/450) m/sec = 5/3 m/sec
Rate in still water = (1/2)*[(10/9) + (5/3)] m/sec.
= 25/18 m/sec
= (25/18)*(18/5) kmph
= 5 kmphIncorrect
Rate upstream = (750/675) = 10/9 m/sec
Rate downstream (750/450) m/sec = 5/3 m/sec
Rate in still water = (1/2)*[(10/9) + (5/3)] m/sec.
= 25/18 m/sec
= (25/18)*(18/5) kmph
= 5 kmph 
Question 10 of 30
10. Question
The speed of a boat in still water is 15 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 12 minutes is
Correct
Speed downstreams =(15 + 3)kmph
= 18 kmph.
Distance travelled = (18 x 12/60)km
= 3.6kmIncorrect
Speed downstreams =(15 + 3)kmph
= 18 kmph.
Distance travelled = (18 x 12/60)km
= 3.6km 
Question 11 of 30
11. Question
A train 100 m long is running at the speed of 30 km / hr. Find the time taken by it to pass a man standing near the railway line.
Correct
Speed of the train = (30 x 5/18_) m / sec = (25/3) m/ sec.
Distance moved in passing the standing man = 100 m.
Required time taken = 100/(25/3) = (100 *(3/25)) sec = 12 sec
Incorrect
Speed of the train = (30 x 5/18_) m / sec = (25/3) m/ sec.
Distance moved in passing the standing man = 100 m.
Required time taken = 100/(25/3) = (100 *(3/25)) sec = 12 sec

Question 12 of 30
12. Question
A train is moving at a speed of 132 km/br. If the length of the train is 110 metres, how long will it take to cross a railway platform 165 metres long?
Correct
Speed of train = 132 *(5/18) m/sec = 110/3 m/sec.
Distance covered in passing the platform = (110 + 165) m = 275 m.
Time taken =275 *(3/110) sec =15/2 sec = 7 ½ sec
Incorrect
Speed of train = 132 *(5/18) m/sec = 110/3 m/sec.
Distance covered in passing the platform = (110 + 165) m = 275 m.
Time taken =275 *(3/110) sec =15/2 sec = 7 ½ sec

Question 13 of 30
13. Question
A man is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the length of the train and its speed?
Correct
Let the length of the train be x metres,
Then, the train covers x metres in 8 seconds and (x + 180) metres in 20 sec
x/8=(x+180)/20 ó 20x = 8 (x + 180) <=> x = 120.
Length of the train = 120 m.
Speed of the train = (120/8) m / sec = m / sec = (15 *18/5) kmph = 54 km
Incorrect
Let the length of the train be x metres,
Then, the train covers x metres in 8 seconds and (x + 180) metres in 20 sec
x/8=(x+180)/20 ó 20x = 8 (x + 180) <=> x = 120.
Length of the train = 120 m.
Speed of the train = (120/8) m / sec = m / sec = (15 *18/5) kmph = 54 km

Question 14 of 30
14. Question
A train 150 m long is running with a speed of 68 kmph. In what time will it pass a man who is running at 8 kmph in the same direction in which the train is going?
Correct
Speed of the train relative to man = (68 – 8) kmph
= (60* 5/18) m/sec = (50/3)m/sec
Time taken by the train to cross the man
= Time taken by It to cover 150 m at 50/3 m / sec = 150 *3/ 50 sec = 9sec
Incorrect
Speed of the train relative to man = (68 – 8) kmph
= (60* 5/18) m/sec = (50/3)m/sec
Time taken by the train to cross the man
= Time taken by It to cover 150 m at 50/3 m / sec = 150 *3/ 50 sec = 9sec

Question 15 of 30
15. Question
A train 220 m long is running with a speed of 59 kmph.. In what will it pass a man who is running at 7 kmph in the direction opposite to that in which the train is going?
Correct
Speed of the train relative to man = (59 + 7) kmph
= 66 *5/18 m/sec = 55/3 m/sec.
Time taken by the train to cross the man = Time taken by it to cover 220 m at (55/3) m / sec = (220 *3/55) sec = 12 sec
Incorrect
Speed of the train relative to man = (59 + 7) kmph
= 66 *5/18 m/sec = 55/3 m/sec.
Time taken by the train to cross the man = Time taken by it to cover 220 m at (55/3) m / sec = (220 *3/55) sec = 12 sec

Question 16 of 30
16. Question
Two trains 137 metres and 163 metres in length are running towards each other on parallel lines, one at the rate of 42 kmph and another at 48 kmpb. In what time will they be clear of each other from the moment they meet?
Correct
Relative speed of the trains = (42 + 48) kmph = 90 kmph
=(90*5/18) m / sec = 25 m /sec.
Time taken by the trains to’pass each other
= Time taken to cover (137 + 163) m at 25 m /sec =(300/25) sec = 12 sec
Incorrect
Relative speed of the trains = (42 + 48) kmph = 90 kmph
=(90*5/18) m / sec = 25 m /sec.
Time taken by the trains to’pass each other
= Time taken to cover (137 + 163) m at 25 m /sec =(300/25) sec = 12 sec

Question 17 of 30
17. Question
Two trains 100 metres and 120 metres long are running in the same direction with speeds of 72 km/hr,In how much time will the first train cross the second?
Correct
Relative speed of the trains = (72 – 54) km/hr = 18 km/hr
= (18 * 5/18) m/sec = 5 m/sec.
Time taken by the trains to cross each other
= Time taken to cover (100 + 120) m at 5 m /sec = (220/5) sec = 44 sec.
Incorrect
Relative speed of the trains = (72 – 54) km/hr = 18 km/hr
= (18 * 5/18) m/sec = 5 m/sec.
Time taken by the trains to cross each other
= Time taken to cover (100 + 120) m at 5 m /sec = (220/5) sec = 44 sec.

Question 18 of 30
18. Question
A train 100 metres long takes 6 seconds to cross a man walking at 5 kmph in the direction opposite to that of the train. Find the speed of the train.?
Correct
Let the speed of the train be x kmph.
Speed of the train relative to man = (x + 5) kmph = (x + 5) *5/18 m/sec.
Therefore 100/((x+5)*5/18)=6 <=> 30 (x + 5) = 1800 <=> x = 55
Speed of the train is 55 kmph.
Incorrect
Let the speed of the train be x kmph.
Speed of the train relative to man = (x + 5) kmph = (x + 5) *5/18 m/sec.
Therefore 100/((x+5)*5/18)=6 <=> 30 (x + 5) = 1800 <=> x = 55
Speed of the train is 55 kmph.

Question 19 of 30
19. Question
A train running at 54 kmph takes 20 seconds to pass a platform. Next it takes.12 sec to pass a man walking at 6 kmph in the same direction in which the train is going . Find the length of the train and the length of the platform.
Correct
Let the length of train be x metres and length of platform be y metres.
Speed of the train relative to man = (54 – 6) kmph = 48 kmph
= 48*(5/18) m/sec = 40/3 m/sec.
In passing a man, the train covers its own length with relative speed.
Length of train = (Relative speed * Time) = ( 40/3)*12 m = 160 m.
Also, speed of the train = 54 *(5/18)m / sec = 15 m / sec.
(x+y)/15 = 20 <=> x + y = 300 <=> Y = (300 – 160) m = 140 m.
Incorrect
Let the length of train be x metres and length of platform be y metres.
Speed of the train relative to man = (54 – 6) kmph = 48 kmph
= 48*(5/18) m/sec = 40/3 m/sec.
In passing a man, the train covers its own length with relative speed.
Length of train = (Relative speed * Time) = ( 40/3)*12 m = 160 m.
Also, speed of the train = 54 *(5/18)m / sec = 15 m / sec.
(x+y)/15 = 20 <=> x + y = 300 <=> Y = (300 – 160) m = 140 m.

Question 20 of 30
20. Question
A man sitting in a train which is traveling at 50 kmph observes that a goods train, traveling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m long, find its speed.?
Correct
Relative speed = 280/9 m / sec = ((280/9)*(18/5)) kmph = 112 kmph.
Speed of goods train = (112 – 50) kmph = 62 kmph.
Incorrect
Relative speed = 280/9 m / sec = ((280/9)*(18/5)) kmph = 112 kmph.
Speed of goods train = (112 – 50) kmph = 62 kmph.

Question 21 of 30
21. Question
A man can row upstream at 7 kmph and downstream at 10kmph.find man’s rate in still water and the rate of current.
Correct
Rate in still water=1/2(10+7)km/hr=8.5 km/hr.
Rate of current=1/2(107)km/hr=1.5 km/hr.
Incorrect
Rate in still water=1/2(10+7)km/hr=8.5 km/hr.
Rate of current=1/2(107)km/hr=1.5 km/hr.

Question 22 of 30
22. Question
A man takes 3 hours 45 minutes to row a boat 15 km downstream of a river and 2hours30minutes to cover a distance of 5km upstream. find the speed of the river current in km/hr.
Correct
. rate downstream=(15/3 ¾)km/hr=(15*4/15)km/hr=4km/hr.
Rate upstream=(5/2 ½)km/hr=(5*2/5)km/hr=2km/hr.
Speed of current=1/2(42)km/hr=1km/hr
Incorrect
. rate downstream=(15/3 ¾)km/hr=(15*4/15)km/hr=4km/hr.
Rate upstream=(5/2 ½)km/hr=(5*2/5)km/hr=2km/hr.
Speed of current=1/2(42)km/hr=1km/hr

Question 23 of 30
23. Question
a man can row 18 kmph in still water.it takes him thrice as long to row up as to row down the river.find the rate of stream.
Correct
Let man’s rate upstream be x kmph.then ,his rate downstream=3xkmph.
So,2x=18 or x=9.
Rate upstream=9 km/hr,rate downstream=27 km/hr.
Hence,rate of stream=1/2(279)km/hr=9 km/hr.
Incorrect
Let man’s rate upstream be x kmph.then ,his rate downstream=3xkmph.
So,2x=18 or x=9.
Rate upstream=9 km/hr,rate downstream=27 km/hr.
Hence,rate of stream=1/2(279)km/hr=9 km/hr.

Question 24 of 30
24. Question
there is a road beside a river.two friends started from a place A,moved to a temple situated at another place B and then returned to A again.one of them moves on a cycle at a speed of 12 km/hr,while the other sails on a boat at a speed of 10 km/hr.if the river flows at the speed of 4 km/hr,which of the two friends will return to placeA first?
Correct
Clearly the cyclist moves both ways at a speed of 12 km/hr.
The boat sailor moves downstream @ (10+4)i.e.,14 km/hr and upstream @ (104)i.e., 6km/hr.
So,average speed of the boat sailor=(2*14*6/14+6)km/hr
=42/5 km/hr=8.4 km/hr.
since the average speed of the cyclist is greater ,he will return ta A first.
Incorrect
Clearly the cyclist moves both ways at a speed of 12 km/hr.
The boat sailor moves downstream @ (10+4)i.e.,14 km/hr and upstream @ (104)i.e., 6km/hr.
So,average speed of the boat sailor=(2*14*6/14+6)km/hr
=42/5 km/hr=8.4 km/hr.
since the average speed of the cyclist is greater ,he will return ta A first.

Question 25 of 30
25. Question
A man can row 7 ½ kmph in still water.if in a river running at 1.5 km/hr an hour,it takes him 50 minutes to row to a place and back,how far off is the place?
Correct
Speed downstream =(7.5+1.5)km/hr=9 km/hr;
Speed upstream=(7.51.5)kmph=6kmph.
Let the required distance be x km.then,
x/9+x/6=50/60.
2x+3x=(5/6*18)
5x=15
x=3.
Hence,the required distance is 3km.
Incorrect
Speed downstream =(7.5+1.5)km/hr=9 km/hr;
Speed upstream=(7.51.5)kmph=6kmph.
Let the required distance be x km.then,
x/9+x/6=50/60.
2x+3x=(5/6*18)
5x=15
x=3.
Hence,the required distance is 3km.

Question 26 of 30
26. Question
In a stream running at 2kmph,a motar boat goes 6km upstream and back again to the starting point in 33 minutes.find the speed of the motarboat in still water.
Correct
let the speed of the motarboat in still water be x kmph.then,
6/x+2 +6/x2=33/60
11x^{2}240x44=0
11x^{2}242x+2x44=0
(x22)(11x+2)=0
x=22.
Incorrect
let the speed of the motarboat in still water be x kmph.then,
6/x+2 +6/x2=33/60
11x^{2}240x44=0
11x^{2}242x+2x44=0
(x22)(11x+2)=0
x=22.

Question 27 of 30
27. Question
A man can row 40km upstream and 55km downstream in 13 hours also, he can row 30km upstream and 44km downstream in 10 hours.find the speed of the man in still water and the speed of the current
Correct
let rate upstream=x km/hr and rate downstream=y km/hr.
Then,40/x +55/y =13…(i) and 30/x +44/y =10
Multiplying (ii) by 4 and (i) by 3 and subtracting ,we get:11/y=1 or y=11.
Substituting y=11 in (i),we get:x=5.
Rate in still water =1/2(11+5)kmph=8kmph.
Rate of current=1/2(115)kmph=3kmph
Incorrect
let rate upstream=x km/hr and rate downstream=y km/hr.
Then,40/x +55/y =13…(i) and 30/x +44/y =10
Multiplying (ii) by 4 and (i) by 3 and subtracting ,we get:11/y=1 or y=11.
Substituting y=11 in (i),we get:x=5.
Rate in still water =1/2(11+5)kmph=8kmph.
Rate of current=1/2(115)kmph=3kmph

Question 28 of 30
28. Question
Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is?
Correct
Ratio of times taken by Sakshi and Tanys = 125:100 = 5:4
Suppose Tanya takes x days to do the work.5:4 :: 20:x => x= 16 days.Hence, Tanya takes 16 days to complete the work.Incorrect
Ratio of times taken by Sakshi and Tanys = 125:100 = 5:4
Suppose Tanya takes x days to do the work.5:4 :: 20:x => x= 16 days.Hence, Tanya takes 16 days to complete the work. 
Question 29 of 30
29. Question
A and B can do a work in 12 days, B and C in 15 days, C and A in 20 days. If A, B and C work together, they will complete the work in?
Correct
(A + B)’s 1 day work = 1/12;
(B + C)’s 1 day work = 1/15;(A + C)’s 1 day work = 1/20Adding, we get: 2(A + B + C)’s 1 day work = (1/12 + 1/15 + 1/20) = 1/5(A + B + C)’s 1 day work = 1/10So, A, B and C together can complete the work in 10 days.Incorrect
(A + B)’s 1 day work = 1/12;
(B + C)’s 1 day work = 1/15;(A + C)’s 1 day work = 1/20Adding, we get: 2(A + B + C)’s 1 day work = (1/12 + 1/15 + 1/20) = 1/5(A + B + C)’s 1 day work = 1/10So, A, B and C together can complete the work in 10 days. 
Question 30 of 30
30. Question
A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days?
Correct
Ratio of times taken by A and B = 100:130 = 10:13
Suppose B takes x days to do the work.x = (23 * 13)/10 = 299/10A’s 1 day work = 1/23; B’s 1 day work = 10/299(A + B)’s 1 day work = (1/23 + 10/299) = 1/13A and B together can complete the job in 13 days.Incorrect
Ratio of times taken by A and B = 100:130 = 10:13
Suppose B takes x days to do the work.x = (23 * 13)/10 = 299/10A’s 1 day work = 1/23; B’s 1 day work = 10/299(A + B)’s 1 day work = (1/23 + 10/299) = 1/13A and B together can complete the job in 13 days.