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Raman`s salary was decreased by 50% and subsequently increased by 50%.How much percent does he lose?
Let the original salary = Rs.100
New final salary=150% of (50% of Rs.100)=
Rs.((150/100)*(50/100)*100)=Rs.75.
Decrease = 25%
Let the original salary = Rs.100
New final salary=150% of (50% of Rs.100)=
Rs.((150/100)*(50/100)*100)=Rs.75.
Decrease = 25%
Sixty five percent of a number is 21 less than four fifth of that number. What is the number ?
Let the number be x.
Then, 4*x/5 –(65% of x) = 21
4x/5 –65x/100 = 21
5 x = 2100
x = 140.
Let the number be x.
Then, 4*x/5 –(65% of x) = 21
4x/5 –65x/100 = 21
5 x = 2100
x = 140.
Which number would replace the question mark in series
7,12,19,?,39
Answer: Option B
Explanation:
Pattern is , +5, +7, +9
Missing Number = 19+9 = 28
Answer: Option B
Explanation:
Pattern is , +5, +7, +9
Missing Number = 19+9 = 28
13, 35, 57, 79, 911, ?
Answer: Option C
Explanation:
The terms of the given series are numbers formed by joining together consecutive odd numbers in order i.e. 1 and 3, 3 and 5, 5 and 7, 7 and 9, 9 and 11, …..
So, missing term = number formed by joining 11 and 13 = 1113.
Answer: Option C
Explanation:
The terms of the given series are numbers formed by joining together consecutive odd numbers in order i.e. 1 and 3, 3 and 5, 5 and 7, 7 and 9, 9 and 11, …..
So, missing term = number formed by joining 11 and 13 = 1113.
In the series 2, 6, 18, 54, … what will be the 8th term ?
Answer: Option D
Explanation:
We can see the given series is in G.P.
as 2*3 = 6, 6*3 = 18, 18*3 = 54
So a = 2 , r = 3
nth term in G.P. is
ar^{n1}
= 2*3{81}
= 2*3^7
= 2*2187 = 4374
Answer: Option D
Explanation:
We can see the given series is in G.P.
as 2*3 = 6, 6*3 = 18, 18*3 = 54
So a = 2 , r = 3
nth term in G.P. is
ar^{n1}
= 2*3{81}
= 2*3^7
= 2*2187 = 4374
Look at this series: 22, 21, 23, 22, 24, 23, … What number should come next?
Answer: Option A
Explanation:
Please look carefully at the series, its pattern is,
1, +2, 1, +2, 1, so next will be +2
23+2 = 25
Answer: Option A
Explanation:
Please look carefully at the series, its pattern is,
1, +2, 1, +2, 1, so next will be +2
23+2 = 25
Look at this series: 544, 509, 474, 439, … What number should come next?
Answer: Option A
Explanation:
This is a simple subtraction series. Each number is 35 less than the previous number.
Answer: Option A
Explanation:
This is a simple subtraction series. Each number is 35 less than the previous number.
Look at this series: 72, 76, 73, 77, 74, __, 75, … What number should fill the blank?
Answer: Option D
Explanation:
This series alternates the addition of 4 with the subtraction of 3.
Answer: Option D
Explanation:
This series alternates the addition of 4 with the subtraction of 3.
In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?
Answer: Option C
Explanation:
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
Then, sum of their values =
x= =50
Hence, the number of 5 p coins = (3 x 50) = 150.
Answer: Option C
Explanation:
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
Then, sum of their values =
x= =50
Hence, the number of 5 p coins = (3 x 50) = 150.
The fourth proportional to 5, 8, 15 is
Answer: Option B
Explanation:
Let the fourth proportional to 5, 8, 15 be x.
Then, 5 : 8 : 15 : x
5x = (8 x 15)
x = =24
Answer: Option B
Explanation:
Let the fourth proportional to 5, 8, 15 be x.
Then, 5 : 8 : 15 : x
5x = (8 x 15)
x = =24
If 0.75 : x :: 5 : 8, then x is equal to
(x x 5) = (0.75 x 8) x =()= 1.205
(x x 5) = (0.75 x 8) x =()= 1.205
Let the boy are 8x and Girls are 5x
=> 5x = 200
=> x = 40
Total students = 8x+5x = 13x = 13(40) = 520
Let the boy are 8x and Girls are 5x
=> 5x = 200
=> x = 40
Total students = 8x+5x = 13x = 13(40) = 520
Let A = 2x, B = 3x, C = 4x, then,
A/B=2x/3x=2/3
B/C=3x/4x=3/4
C/A=4x/2x=2/1
=>
A/B:B/C:C/A=2/3:3/4:2/1=8:9:24
Let A = 2x, B = 3x, C = 4x, then,
A/B=2x/3x=2/3
B/C=3x/4x=3/4
C/A=4x/2x=2/1
=>
A/B:B/C:C/A=2/3:3/4:2/1=8:9:24
Treat 2:9 as 2/9 and x:18 as x/18, treat :: as =
So we get 2/9 = x/18
=> 9x = 36
=> x = 4
Treat 2:9 as 2/9 and x:18 as x/18, treat :: as =
So we get 2/9 = x/18
=> 9x = 36
=> x = 4
If a:b = 2:3 and b:c = 4:3, then find a:b:c
Answer: Option A
Explanation:
a:b=2:3
b:c=4:3=(4*)=
a:b:c=2:3:=8:12:9
Answer: Option A
Explanation:
a:b=2:3
b:c=4:3=(4*)=
a:b:c=2:3:=8:12:9
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option B
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y – x) = (2y – x) = y = 2x.
Profit = Rs. (y – x) = Rs. (2x – x) = Rs. x.
Profit % =(x/x x 100)% = 100%
Answer: Option B
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y – x) = (2y – x) = y = 2x.
Profit = Rs. (y – x) = Rs. (2x – x) = Rs. x.
Profit % =(x/x x 100)% = 100%
A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Rs. 392, what was his profit?
Answer: Option C
Explanation:
C.P.=Rs.(
Rs.=Rs.320
Profit = Rs. (392 – 320) = Rs. 72.
Answer: Option C
Explanation:
C.P.=Rs.(
Rs.=Rs.320
Profit = Rs. (392 – 320) = Rs. 72.
Answer: Option B
Explanation:
Let the Cost price of article is Rs. x
Required ratio =
104% of x/106% of x=104/106=52/53=52:53
Answer: Option B
Explanation:
Let the Cost price of article is Rs. x
Required ratio =
104% of x/106% of x=104/106=52/53=52:53
If the cost price is 25% of selling price. Then what is the profit percent.
Answer: Option C
Explanation:
Let the S.P = 100
then C.P. = 25
Profit = 75
Profit% = 75/25 * 100 = 3005
Answer: Option C
Explanation:
Let the S.P = 100
then C.P. = 25
Profit = 75
Profit% = 75/25 * 100 = 3005
Answer: Option C
Explanation:
Let the new S.P. be x, then.
(100 – loss%):(1st S.P.) = (100 + gain%):(2nd S.P.)
=(95/1140=105/x)
=x=1260
Answer: Option C
Explanation:
Let the new S.P. be x, then.
(100 – loss%):(1st S.P.) = (100 + gain%):(2nd S.P.)
=(95/1140=105/x)
=x=1260
man buys an article for Rs. 27.50 and sells it for Rs 28.60. Find his gain percent
Answer: Option D
Explanation:
So we have C.P. = 27.50
S.P. = 28.60
Gain = 28.60 – 27.50 = Rs. 1.10
Gain%=(Gain/Cost∗100)%=(1.10/27.50∗100)%=4%
Answer: Option D
Explanation:
So we have C.P. = 27.50
S.P. = 28.60
Gain = 28.60 – 27.50 = Rs. 1.10
Gain%=(Gain/Cost∗100)%=(1.10/27.50∗100)%=4%
A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
Answer: Option A
Explanation:
Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs. [ (6500 x 6) – 34009 ]
= Rs. (39000 – 34009)
= Rs. 4991.
Answer: Option A
Explanation:
Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs. [ (6500 x 6) – 34009 ]
= Rs. (39000 – 34009)
= Rs. 4991.
The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?
Answer: Option D
Explanation:
Average of 20 numbers = 0.
Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (a).
Answer: Option D
Explanation:
Average of 20 numbers = 0.
Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (a).
Average of all prime numbers between 30 to 50
Answer: Option D
Explanation:
Prime numbers between 30 and 50 are:
31, 37, 41, 43, 47
Average of prime numbers between 30 to 50 will be
= =39.8
Answer: Option D
Explanation:
Prime numbers between 30 and 50 are:
31, 37, 41, 43, 47
Average of prime numbers between 30 to 50 will be
= =39.8
Find the sum of first 30 natural numbers
Answer: Option C
Explanation:
Sum of n natural numbers
=n(n+1)2
=n(n+1)2
=30(30+1)/2=30(31)/2=465
Answer: Option C
Explanation:
Sum of n natural numbers
=n(n+1)2
=n(n+1)2
=30(30+1)/2=30(31)/2=465
Average age of boys in a class is 16 years and average age of girls is 15 years, what is the average age of all
Answer: Option D
Explanation:
As number of girls and boys is not given so result cant be computed
Answer: Option D
Explanation:
As number of girls and boys is not given so result cant be computed
A batsman makes a score of 87 runs in the 17th match and thus increases his average by 3. Find his average after 17th match
Answer: Option D
Explanation:
Let the average after 17th match is x
then the average before 17th match is x3
so 16(x3) + 87 = 17x
=> x = 87 – 48 = 39
Answer: Option D
Explanation:
Let the average after 17th match is x
then the average before 17th match is x3
so 16(x3) + 87 = 17x
=> x = 87 – 48 = 39
A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
Answer: Option B
Explanation:
Speed =( ) = 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
=(2* )
= 7.2 km/hr.
Answer: Option B
Explanation:
Speed =( ) = 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
=(2* )
= 7.2 km/hr.
A does half as much work as B in threefourth of the time. If together they take 18 days to complete the work, how much time shall B take to do it
Answer: Option C
Explanation:
Suppose B takes x dáys to do the work.
As per question A will take
2∗3/4∗x=3x/2days
(A+B)s 1 days work= 1/18
1/x + 2/3x = 1/18 or x = 30 days
Answer: Option C
Explanation:
Suppose B takes x dáys to do the work.
As per question A will take
2∗3/4∗x=3x/2days
(A+B)s 1 days work= 1/18
1/x + 2/3x = 1/18 or x = 30 days
A bank offers 5% compound interest calculated on halfyearly basis. A customer deposits Rs. 1600 each on 1^{st}January and 1^{st} July of a year. At the end of the year, the amount he would have gained by way of interest is:
Answer: Option B
Explanation:
Amount= Rs. [1600*(1+)^2+1600(1+)]
= Rs.[1600**+1600*]
=Rs.[1600**+1)]
Rs.
= Rs. 3321.
C.I. = Rs. (3321  3200) = Rs. 121
Answer: Option B
Explanation:
Amount= Rs. [1600*(1+)^2+1600(1+)]
= Rs.[1600**+1600*]
=Rs.[1600**+1)]
Rs.
= Rs. 3321.
C.I. = Rs. (3321  3200) = Rs. 121
Which of the following is the solution of 2x + 3 ≤ 9 in the real numbers?
If 2x +3 ≤ 9 then 2x ≤ 6 and x ≤ 3.
If 2x +3 ≤ 9 then 2x ≤ 6 and x ≤ 3.
A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
Suppose a container contains xx units of a liquid from which yy units are taken out and replaced by water. After nn operations, quantity of pure liquid
x units.
milk contained by the container now
=40
=40
=
=
=29.16
Suppose a container contains xx units of a liquid from which yy units are taken out and replaced by water. After nn operations, quantity of pure liquid
x units.
milk contained by the container now
=40
=40
=
=
=29.16
In how many different ways can the letters of the word ‘OPTICAL’ be arranged so that the vowels always come together?
The word ‘OPTICAL’ has 7 letters. It has the vowels ‘O’,’I’,’A’ in it and these 3 vowels should always come together. Hence these three vowels can be grouped and considered as a single letter. That is, PTCL(OIA).
Hence we can assume total letters as 5 and all these letters are different.
Number of ways to arrange these letters
=5!=5×4×3×2×1=120=5!=5×4×3×2×1=120
All the 3 vowels (OIA) are different
Number of ways to arrange these vowels among themselves
=3!=3×2×1=6=3!=3×2×1=6
Hence, required number of ways
=120×6=720
The word ‘OPTICAL’ has 7 letters. It has the vowels ‘O’,’I’,’A’ in it and these 3 vowels should always come together. Hence these three vowels can be grouped and considered as a single letter. That is, PTCL(OIA).
Hence we can assume total letters as 5 and all these letters are different.
Number of ways to arrange these letters
=5!=5×4×3×2×1=120=5!=5×4×3×2×1=120
All the 3 vowels (OIA) are different
Number of ways to arrange these vowels among themselves
=3!=3×2×1=6=3!=3×2×1=6
Hence, required number of ways
=120×6=720
Look at this series: 2, 1, (1/2), (1/4), … What number should come next?
Answer: Option B
Explanation:
This is a simple division series; each number is onehalf of the previous number.
In other terms to say, the number is divided by 2 successively to get the next result.
4/2 = 2
2/2 = 1
1/2 = 1/2
(1/2)/2 = 1/4
(1/4)/2 = 1/8 and so on.
Answer: Option B
Explanation:
This is a simple division series; each number is onehalf of the previous number.
In other terms to say, the number is divided by 2 successively to get the next result.
4/2 = 2
2/2 = 1
1/2 = 1/2
(1/2)/2 = 1/4
(1/4)/2 = 1/8 and so on.
Look carefully for the pattern, and then choose which pair of numbers comes next.
2 44 4 41 6 38 8
Explanation: Here, there are two alternating patterns, one addition and one subtraction. The first starts with 2 and increases by 2; the second starts with 44 and decreases by 3.
Explanation: Here, there are two alternating patterns, one addition and one subtraction. The first starts with 2 and increases by 2; the second starts with 44 and decreases by 3.
Look carefully for the pattern, and then choose which pair of numbers comes next.
17 32 19 29 21 26 23
Explanation: Here, there are two alternating patterns. The first begins with 17 and adds 2; the second begins with 32 and subtracts 3.
Explanation: Here, there are two alternating patterns. The first begins with 17 and adds 2; the second begins with 32 and subtracts 3.
Look carefully for the pattern, and then choose which pair of numbers comes next.
11 14 14 17 17 20 20
Explanation: This is a simple addition series with repetition. It adds 3 to each number to arrive at the next, which is repeated before 3 is added again.
Explanation: This is a simple addition series with repetition. It adds 3 to each number to arrive at the next, which is repeated before 3 is added again.
SCD, TEF, UGH, ____, WKL
Explanation
There are two alphabetical series here. The first series is with the first letters only: STUVW. The second series involves the remaining letters: CD, EF, GH, IJ, KL.
Explanation
There are two alphabetical series here. The first series is with the first letters only: STUVW. The second series involves the remaining letters: CD, EF, GH, IJ, KL.
B_{2}CD, _____, BCD_{4}, B_{5}CD, BC_{6}D
Explanation:
Explanation:
If TAP is coded as SZO, then how is FREEZE coded ?
Answer: Option B
Explanation:
Clearly,
T 1 = S
A 1 = Z
P 1 = O
So FREEZE will be,
F 1 E
R 1 Q
E 1 D
E 1 D
Z 1 Y
E 1 D
Answer: Option B
Explanation:
Clearly,
T 1 = S
A 1 = Z
P 1 = O
So FREEZE will be,
F 1 E
R 1 Q
E 1 D
E 1 D
Z 1 Y
E 1 D
FAG, GAF, HAI, IAH, ____
Explanation:
Explanation:
If GIVE is coded as 5137 and BAT is coded as 924 how is GATE coded ?
Answer: C. 5247
Explanation:
Clearly it can be seen that G is coded as 5, A 2 , T – 4, E – 7. So GATE =5247
Answer: C. 5247
Explanation:
Clearly it can be seen that G is coded as 5, A 2 , T – 4, E – 7. So GATE =5247
If FISH is written as EHRG in a certain code, how would JUNGLE be written in that code ?
Answer: A. ITMFKD
Explanation:
Each letter in the word is moved one step forward to obtain the corresponding letter of the code.
Answer: A. ITMFKD
Explanation:
Each letter in the word is moved one step forward to obtain the corresponding letter of the code.
ELFA, GLHA, ILJA, _____, MLNA
Explanation:
The second and forth letters in the series, L and A, are static. The first and third letters consist of an alphabetical order beginning with the letter E.
Explanation:
The second and forth letters in the series, L and A, are static. The first and third letters consist of an alphabetical order beginning with the letter E.
If SUMMER is coded as RUNNER, the code for WINTER will be ?
Answer: B. VIOUER
Explanation:
The first letter of the word is moved one step backward, while the two middle letters are each moved one step forward to obtain the corresponding letters of the code.
Answer: B. VIOUER
Explanation:
The first letter of the word is moved one step backward, while the two middle letters are each moved one step forward to obtain the corresponding letters of the code.
If PALE is coded as 2134, EARTH is coded as 41590, how can is PEARL be coded in that language?
Answer / Explanation
Answer : D.
The letters are coded accordingly P as 2, E as 4, A as 1, R as 5 and L as 3. So PEARL is coded as 24153.
Answer / Explanation
Answer : D.
The letters are coded accordingly P as 2, E as 4, A as 1, R as 5 and L as 3. So PEARL is coded as 24153.
Pointing to a man, a woman said, “His mother is the only daughter of my mother.” How is the woman related to the man ?
Answer: Option A
Explanation:
Blood relation Analysis :
only daughter of my mother > means herself
So she is his mother.
Answer: Option A
Explanation:
Blood relation Analysis :
only daughter of my mother > means herself
So she is his mother.
Pointing to a photograph, a man said, “I have no brother or sister but that man’s father is my father’s son.” Whose photograph was it ?
Answer: Option B
Explanation:
Since the person who is telling has no brother or sister, so his father son is he himself.
So the man in the photograph is his son.
Answer: Option B
Explanation:
Since the person who is telling has no brother or sister, so his father son is he himself.
So the man in the photograph is his son.
If Kamal says, “Ravi’s mother is the only daughter of my mother”, how is Kamal related to Ravi ?
Answer: Option C
Explanation:
Only daughter of my mother = Kamal Sister
Kamal Sister is Ravi’s Mother
So Kamal is maternal uncle of Ravi
Answer: Option C
Explanation:
Only daughter of my mother = Kamal Sister
Kamal Sister is Ravi’s Mother
So Kamal is maternal uncle of Ravi
A’s father is B’s soninlaw. C, A’s sister, is the daughter of P. How is P related to B
Answer: Option D
Answer: Option D
The total of the ages of Amar, Akbar and Anthony is 80 years. What was the total of their ages three years ago ?
Explanation :
Required sum = (80 – 3 x 3) years = (80 – 9) years = 71 years.
Explanation :
Required sum = (80 – 3 x 3) years = (80 – 9) years = 71 years.
A woman says, “If you reverse my own age, the figures represent my husband’s age. He is, of course, senior to me and the difference between our ages is oneeleventh of their sum.” The woman’s age is
Let x and y be the ten’s and unit’s digits respectively of the numeral denoting the woman’s age.
Then, woman’s age = (10X + y) years; husband’s age = (10y + x) years.
Therefore (10y + x) (10X + y) = (1/11) (10y + x + 10x + y)
(9y9x) = (1/11)(11y + 11x) = (x + y) 10x = 8y x = (4/5)y
Clearly, y should be a singledigit multiple of 5, which is 5.
So, x = 4, y = 5.
Hence, woman’s age = 10x + y = 45 years.
Let x and y be the ten’s and unit’s digits respectively of the numeral denoting the woman’s age.
Then, woman’s age = (10X + y) years; husband’s age = (10y + x) years.
Therefore (10y + x) (10X + y) = (1/11) (10y + x + 10x + y)
(9y9x) = (1/11)(11y + 11x) = (x + y) 10x = 8y x = (4/5)y
Clearly, y should be a singledigit multiple of 5, which is 5.
So, x = 4, y = 5.
Hence, woman’s age = 10x + y = 45 years.
What is the product of all the numbers in the dial of a telephone ?
Explanation :
Since one of the numbers on the dial of a telephone is zero, so the product of all the numbers on it is 0.
Explanation :
Since one of the numbers on the dial of a telephone is zero, so the product of all the numbers on it is 0.
A pineapple costs Rs. 7 each. A watermelon costs Rs. 5 each. X spends Rs. 38 on these fruits. The number of pineapples purchased is
EXplanation:
Let the number of pineapples and watermelons be x and y respectively.
Then, 7x+5y=38 or 5y=(387x) or y=
Clearly, yis a whole number, only when (387x) is divisible by 5.
This happen when x=4.
EXplanation:
Let the number of pineapples and watermelons be x and y respectively.
Then, 7x+5y=38 or 5y=(387x) or y=
Clearly, yis a whole number, only when (387x) is divisible by 5.
This happen when x=4.
Find the odd man out 3, 5, 11, 14, 17, 21
Each of the numbers except 14 is an odd number.
The number ’14’ is the only EVEN number.
Each of the numbers except 14 is an odd number.
The number ’14’ is the only EVEN number.
Find the odd man out 6, 9, 15, 21, 24, 28, 30
Each of the numbers except 28, is a multiple of 3.
Each of the numbers except 28, is a multiple of 3.
Find out the wrong number in the given sequence of numbers 52, 51, 48, 43, 34, 27, 16
Subtract 1, 3, 5, 7, 9, 11 from successive numbers.
So, 34 is wrong.
Subtract 1, 3, 5, 7, 9, 11 from successive numbers.
So, 34 is wrong.
Find the odd man out.
41, 43, 47, 53, 61, 71, 73, 81
Each of the numbers except 81 is a prime number.
Each of the numbers except 81 is a prime number.
In a one day cricket match, the total runs made by a team were 200. Out of these 160 runs were made by spinners.
Conclusions:
I. 80% of the team consists of spinners.
II. The opening batsmen were spinners.
According to the statement, 80% of the total runs were made by spinners. So, I does not follow. Nothing about the opening batsmen is mentioned in the statement. So, II also does not follow.
According to the statement, 80% of the total runs were made by spinners. So, I does not follow. Nothing about the opening batsmen is mentioned in the statement. So, II also does not follow.
Statements: The manager humiliated Sachin in the presence of his colleagues.
Conclusions:
The manager might have humiliated Sachin not because of his dislike but on account of certain negligence or mistake on his part. So, I does not follow. Also, nothing about Sachin’s rapport with his colleagues can be deduced from the statement. So, II also does not follow.
Statements: Jade plant has thick leaves and it requires little water.
Conclusions:
I.All plants with thick leaves require little water.
II.Jade plants may be grown in places where water is not in abundance.
The statement talks of jade plants only and not ‘all plants with thick leaves’. So, I does not follow. Also, since jade plants require little water, so they can be grown in places where water is not in abundance. So, II follows.
The statement talks of jade plants only and not ‘all plants with thick leaves’. So, I does not follow. Also, since jade plants require little water, so they can be grown in places where water is not in abundance. So, II follows.
Statements: Use “Kraft” colours. They add colour to our life. – An advertisement.
Conclusions:
The slogan given in the statement is definitely a catchy one which indicates that catchy slogans do attract people. So, I does not follow. Nothing about people’s preference for colours can be deduced from the statement. Thus, II also does not follow.
The slogan given in the statement is definitely a catchy one which indicates that catchy slogans do attract people. So, I does not follow. Nothing about people’s preference for colours can be deduced from the statement. Thus, II also does not follow.
Kanmani ranked sixteenth from the top and twenty ninth from the bottom among those who passed an examination. Six boys did not participate in the competition and five failed in it. How many boys were there in the class?
Number of boys who passed = (15 + 1 + 28) = 44
Total number of boys in the class = 44 + 6 +5 = 55.
Number of boys who passed = (15 + 1 + 28) = 44
Total number of boys in the class = 44 + 6 +5 = 55.
Some boys are sitting in a row. P is sitting fourteenth from the left and Q is seventh from the right. If there are four boys between P and Q, how many boys are there in the row?
Number of boys in the row = number of boys up til P + number of boys between P and Q + number of boys including Q and those behind Q = 14 + 4 + 7 = 25.
Number of boys in the row = number of boys up til P + number of boys between P and Q + number of boys including Q and those behind Q = 14 + 4 + 7 = 25.
Look at this series: 7, 10, 8, 11, 9, 12, … What number should come next?
This is a simple alternating addition and subtraction series. In the first pattern, 3 is added; in the second, 2 is subtracted
This is a simple alternating addition and subtraction series. In the first pattern, 3 is added; in the second, 2 is subtracted
Look at this series: 58, 52, 46, 40, 34, … What number should come next?
This is a simple subtraction series. Each number is 6 less than the previous number.
This is a simple subtraction series. Each number is 6 less than the previous number.
Look at this series: 544, 509, 474, 439, … What number should come next?
This is a simple subtraction series. Each number is 35 less than the previous number.
This is a simple subtraction series. Each number is 35 less than the previous number.
Look at this series: 8, 6, 9, 23, 87 , … What number should come next?
8 x 1 – 2 = 6
6 x 2 – 3 = 9
9 x 3 – 4 = 23
23 x 4 – 5 = 87
87 x 5 – 6 = 429 …
8 x 1 – 2 = 6
6 x 2 – 3 = 9
9 x 3 – 4 = 23
23 x 4 – 5 = 87
87 x 5 – 6 = 429 …
But I did not want to shoot the elephant. I watched him beating his bunch of grass against his knees, with the preoccupied grandmotherly air that elephants have. It seemed to me that it would be murder to shoot him. I had never shot an elephant and never wanted to. (Somehow it always seems worse to kill large animal.) Besides, there was the beast’s owner to be considered. But I had got to act quickly. I turned to some experiencedlooking Burmans who had been there when we arrived, and asked them how the elephants had been behaving. They all said the same thing; he took no notice of you if you left him alone, but he might charge if you went too close to him.
Question 1 : The phrase ‘Preoccupied grandmotherly air’ signifies
Question 2: From the passage it appears that the author was
Question 3 : The author did not want to shoot the elephant because he
Watermelons …(1)… to India by the 4^{th} century AD. Sushruta, the great Indian physician …(2)… wrote Sushruta Samhita mentions that watermelons were grown …(3)… the banks of the river Indus …(4)… are also mentioned in ancient books. Sushruta calls it as Kalinda or Kalinga (hence Kalingad in Marathi). It was …(5)… to China in the 10^{th} or 11^{th} century and …(6)… it is grown throughout the tropics. Wild watermelons are …(7)… compared to cultivated ones; some of which weigh up to 25 kg. The heaviest fruit weighing 118 kg was produced at Hope, Arkansas, USA the state to which President Clinton …(8)…
Question : 1
Question 2:
Question 3:
Question 4
Question 5:
Question 6:
Question 7:
Question 8:
Steel prices, which have been on the rise for last several years, have ————the backbone of auto parts industry
Adopting healthy habits is vital in curbing the spread of H1N1, and it is high time people ———–it.
It is ————for children, elderly and people suffering from lung diseases to avoid going out early in the morning.
Since ————on mango trees is a very sensitive period, any weather change can badly hit its productivity and quality
The —————should understand that they would get a licence only if they have basic skills of driving.
Rearrange the following six sentences (A), (B), (C), (D), (E) and (F) in the proper sequence to form a meaningful paragraph; then answer the questions given below them.
(A) It is therefore a contributing factor to the growth of landfills and waterway pollution, both of which are costly and energyintensive to solve.
(B) Making an effort to use those resources and avoid polystyrene ones can help to decrease your environmental impact.
(C) Nonbiodegradable essentially means that any polystyrene that makes its way into a landfill will stay there indefinitely, never breaking down and returning to the earth.
(D) Polystyrene, as a product, is very convenient to use, but it has some important effects we should consider when making choices as consumers,
(E) While recycling polystyrene material can cushion the environmental blow of its use, alternatives are available that are created from renewable resources and biodegrade more readily.
(F) For example, while polystyrene has some excellent uses and is technically recyclable, it is not a substance that biodegrades
Question 1 : Which of the following should be the LAST (SIXTH) sentence after rearrangement?
Question 2 : Which of the following should be the FOURTH sentence after rearrangement?
Question 3 : Which of the following should be the FIRST sentence after rearrangement?
Question 4 : Which of the following should be the SECOND sentence after rearrangement?
Question 5 : Which of the following should be the FIFTH sentence after rearrangement?
The tunnel was so ……… and congested, that we became ………
The following piechart shows the sources of funds to be collected by the National Highways Authority of India (NHAI) for its Phase II projects. Study the piechart and answers the question that follow.
Question 1: Near about 20% of the funds are to be arranged through:
20% of the total funds to be arranged = Rs. (20% of 57600) crores
= Rs. 11520 crores
Rs. 11486 crores.
Rs. 11486 crores is the amount of funds to be arranged through External Assistance
20% of the total funds to be arranged = Rs. (20% of 57600) crores
= Rs. 11520 crores
Rs. 11486 crores.
Rs. 11486 crores is the amount of funds to be arranged through External Assistance
If NHAI could receive a total of Rs. 9695 crores as External Assistance, by what percent (approximately) should it increase the Market Borrowing to arrange for the shortage of funds?
Shortage of funds arranged through External Assistance= Rs. (11486 – 9695) crores
= Rs. 1791 crores.
Increase required in Market Borrowing = Rs. 1791 crores.
Percentage increase required =(* 100)%=5.98%
=6%(approx.)
Shortage of funds arranged through External Assistance= Rs. (11486 – 9695) crores
= Rs. 1791 crores.
Increase required in Market Borrowing = Rs. 1791 crores.
Percentage increase required =(* 100)%=5.98%
=6%(approx.)
If the toll is to be collected through an outsourced agency by allowing a maximum 10% commission, how much amount should be permitted to be collected by the outsourced agency, so that the project is supported with Rs. 4910 crores?
Amount permitted = (Funds required from Toll for projects of Phase II) +
(10% of these funds)
= Rs. 4910 crores + Rs. (10% of 4910) crores
= Rs. (4910 + 491) crores
= Rs. 5401 crores.
Amount permitted = (Funds required from Toll for projects of Phase II) +
(10% of these funds)
= Rs. 4910 crores + Rs. (10% of 4910) crores
= Rs. (4910 + 491) crores
= Rs. 5401 crores.
The central angle corresponding to Market Borrowing is
Central angle corresponding to Market Borrowing
=)x 360º= 187.2º
Central angle corresponding to Market Borrowing
=)x 360º= 187.2º
The approximate ratio of the funds to be arranged through Toll and that through Market Borrowing is
Reqiured ratio = )
=
= approx.
Reqiured ratio = )
=
= approx.
(17)^{3.5} x (17)^{?} = 17^{8}
Let (17)^{3.5} x (17)^{x} = 17^{8}.
Then, (17)^{3.5 + x} = 17^{8}.
3.5 + x = 8
x = (8 – 3.5)
x = 4.5
Let (17)^{3.5} x (17)^{x} = 17^{8}.
Then, (17)^{3.5 + x} = 17^{8}.
3.5 + x = 8
x = (8 – 3.5)
x = 4.5
If 3^{(x – y)} = 27 and 3^{(x + y)} = 243, then x is equal to:
3^{x – y} = 27 = 3^{3} x – y = 3 ….(i)
3^{x + y} = 243 = 3^{5} x + y = 5 ….(ii)
On solving (i) and (ii), we get x = 4.
3^{x – y} = 27 = 3^{3} x – y = 3 ….(i)
3^{x + y} = 243 = 3^{5} x + y = 5 ….(ii)
On solving (i) and (ii), we get x = 4.
(25)^{7.5} x (5)^{2.5} ÷ (125)^{1.5} = 5^{?}
Let (25)^{7.5} x (5)^{2.5} ÷ (125)^{1.5} = 5^{x}.
Then,  (5^{2})^{7.5} x (5)^{2.5}  = 5^{x} 
(5^{3})^{1.5} 
5^{(2 x 7.5)} x 5^{2.5}  = 5x  
5^{(3 x 1.5)} 
5^{15} x 5^{2.5}  = 5^{x}  
5^{4.5} 
5^{x} = 5^{(15 + 2.5 – 4.5)}
5^{x} = 5^{13}
x = 13.
Let (25)^{7.5} x (5)^{2.5} ÷ (125)^{1.5} = 5^{x}.
Then,  (5^{2})^{7.5} x (5)^{2.5}  = 5^{x} 
(5^{3})^{1.5} 
5^{(2 x 7.5)} x 5^{2.5}  = 5x  
5^{(3 x 1.5)} 
5^{15} x 5^{2.5}  = 5^{x}  
5^{4.5} 
5^{x} = 5^{(15 + 2.5 – 4.5)}
5^{x} = 5^{13}
x = 13.
If m and n are whole numbers such that mn = 121, the value of (m – 1)n + 1 is:
We know that 11^{2} = 121.
Putting m = 11 and n = 2, we get:
(m – 1)^{n + 1} = (11 – 1)^{(2 + 1)} = 10^{3} = 1000.
We know that 11^{2} = 121.
Putting m = 11 and n = 2, we get:
(m – 1)^{n + 1} = (11 – 1)^{(2 + 1)} = 10^{3} = 1000.
If = 3125, then the value of is:
= 3125
=
a = 5.
Then =
=
= 25.
= 3125
=
a = 5.
Then =
=
= 25.