Complete Aptitude Quiz: New
Must have Quiz to Know the tricks for Bank Exams: PO, Clerk, SO
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Number of Questions: 50
Time: 30 Minutes
Category: Aptitude
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Question 1 of 50
1. Question
If a:b = 2:3 and b:c = 4:3, then find a:b:c
Correct
Answer: Option A
Explanation:
a:b=2:3
b:c=4:3=(4*)=
a:b:c=2:3:=8:12:9Incorrect
Answer: Option A
Explanation:
a:b=2:3
b:c=4:3=(4*)=
a:b:c=2:3:=8:12:9 
Question 2 of 50
2. Question
If A:B:C = 2:3:4, then find
Correct
Let A = 2x, B = 3x, C = 4x, then,
A/B=2x/3x=2/3
B/C=3x/4x=3/4
C/A=4x/2x=2/1
=>
A/B:B/C:C/A=2/3:3/4:2/1=8:9:24Incorrect
Let A = 2x, B = 3x, C = 4x, then,
A/B=2x/3x=2/3
B/C=3x/4x=3/4
C/A=4x/2x=2/1
=>
A/B:B/C:C/A=2/3:3/4:2/1=8:9:24 
Question 3 of 50
3. Question
In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?
Correct
Answer: Option C
Explanation:
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
Then, sum of their values =
x= =50Hence, the number of 5 p coins = (3 x 50) = 150.
Incorrect
Answer: Option C
Explanation:
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
Then, sum of their values =
x= =50Hence, the number of 5 p coins = (3 x 50) = 150.

Question 4 of 50
4. Question
man buys an article for Rs. 27.50 and sells it for Rs 28.60. Find his gain percent
Correct
Answer: Option D
Explanation:
So we have C.P. = 27.50
S.P. = 28.60Gain = 28.60 – 27.50 = Rs. 1.10
Gain%=(Gain/Cost∗100)%=(1.10/27.50∗100)%=4%
Incorrect
Answer: Option D
Explanation:
So we have C.P. = 27.50
S.P. = 28.60Gain = 28.60 – 27.50 = Rs. 1.10
Gain%=(Gain/Cost∗100)%=(1.10/27.50∗100)%=4%

Question 5 of 50
5. Question
If the cost price is 25% of selling price. Then what is the profit percent.
Correct
Answer: Option C
Explanation:
Let the S.P = 100
then C.P. = 25Profit = 75
Profit% = 75/25 * 100 = 3005
Incorrect
Answer: Option C
Explanation:
Let the S.P = 100
then C.P. = 25Profit = 75
Profit% = 75/25 * 100 = 3005

Question 6 of 50
6. Question
A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Rs. 392, what was his profit?
Correct
Answer: Option C
Explanation:
C.P.=Rs.(
Rs.=Rs.320Profit = Rs. (392 – 320) = Rs. 72.
Incorrect
Answer: Option C
Explanation:
C.P.=Rs.(
Rs.=Rs.320Profit = Rs. (392 – 320) = Rs. 72.

Question 7 of 50
7. Question
The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:
Correct
Answer: Option D
Explanation:
Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135 …. (i)
A + B = (40 x 2) = 80 …. (ii)
B + C = (43 x 2) = 86 ….(iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 …. (iv)
Subtracting (i) from (iv), we get : B = 31.
B’s weight = 31 kg.
Incorrect
Answer: Option D
Explanation:
Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135 …. (i)
A + B = (40 x 2) = 80 …. (ii)
B + C = (43 x 2) = 86 ….(iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 …. (iv)
Subtracting (i) from (iv), we get : B = 31.
B’s weight = 31 kg.

Question 8 of 50
8. Question
Average age of boys in a class is 16 years and average age of girls is 15 years, what is the average age of all
Correct
Answer: Option D
Explanation:
As number of girls and boys is not given so result cant be computed
Incorrect
Answer: Option D
Explanation:
As number of girls and boys is not given so result cant be computed

Question 9 of 50
9. Question
In an examination, 34% of the students failed in mathematics and 42% failed in English. If 20% of the students failed in both the subjects, then find the percentage of students who passed in both the subjects.
Correct
Answer: Option C
Explanation:
Failed in mathematics, n(A) = 34
Failed in English, n(B) = 42
n(A∪B)=n(A)+n(B)−n(A∩B)=34+42−20=56Failed in either or both subjects are 56Percentage passed = (100−56)%=44%Incorrect
Answer: Option C
Explanation:
Failed in mathematics, n(A) = 34
Failed in English, n(B) = 42
n(A∪B)=n(A)+n(B)−n(A∩B)=34+42−20=56Failed in either or both subjects are 56Percentage passed = (100−56)%=44% 
Question 10 of 50
10. Question
Income of A is 25% more than the income of B. What is the income of B in terms of income of A?
Correct
ANSWER: A
Explanation:
One of the most basic questions.Let income of B be 100. Income of A is 25% more than income of B which means Income of A becomes 125
Now income of B in terms of A = 100/125 *100 = 80%
Incorrect
ANSWER: A
Explanation:
One of the most basic questions.Let income of B be 100. Income of A is 25% more than income of B which means Income of A becomes 125
Now income of B in terms of A = 100/125 *100 = 80%

Question 11 of 50
11. Question
Which number would replace the question mark in series
7,12,19,?,39Correct
Answer: Option B
Explanation:
Pattern is , +5, +7, +9
Missing Number = 19+9 = 28Incorrect
Answer: Option B
Explanation:
Pattern is , +5, +7, +9
Missing Number = 19+9 = 28 
Question 12 of 50
12. Question
In the series 2, 6, 18, 54, … what will be the 8th term ?
Correct
Answer: Option D
Explanation:
We can see the given series is in G.P.
as 2*3 = 6, 6*3 = 18, 18*3 = 54
So a = 2 , r = 3
nth term in G.P. is
ar^{n1}
= 2*3{81}
= 2*3^7
= 2*2187 = 4374Incorrect
Answer: Option D
Explanation:
We can see the given series is in G.P.
as 2*3 = 6, 6*3 = 18, 18*3 = 54
So a = 2 , r = 3
nth term in G.P. is
ar^{n1}
= 2*3{81}
= 2*3^7
= 2*2187 = 4374 
Question 13 of 50
13. Question
On dividing a number by 56, we get 29 as remainder. On dividing the same number by 8, what will be the remainder ?
Correct
Answer: Option B
Explanation:
Formula: (Divisor*Quotient) + Remainder = Dividend.
Soln:
(56*Q)+29 = D ——(1)
D%8 = R ————(2)
From equation(2),
((56*Q)+29)%8 = R.
Assume Q = 1.
(56+29)%8 = R.
85%8 = R
5 = R.
Incorrect
Answer: Option B
Explanation:
Formula: (Divisor*Quotient) + Remainder = Dividend.
Soln:
(56*Q)+29 = D ——(1)
D%8 = R ————(2)
From equation(2),
((56*Q)+29)%8 = R.
Assume Q = 1.
(56+29)%8 = R.
85%8 = R
5 = R.

Question 14 of 50
14. Question
A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
Correct
Answer: Option B
Explanation:
Speed =( ) = 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
=(2* )
= 7.2 km/hr.Incorrect
Answer: Option B
Explanation:
Speed =( ) = 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
=(2* )
= 7.2 km/hr. 
Question 15 of 50
15. Question
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Correct
Solution:
Option(D) is correctDue to stoppages, it covers 9 km less.
Time taken to cover 9 km = 9/54×60 = 10 min.
Incorrect
Solution:
Option(D) is correctDue to stoppages, it covers 9 km less.
Time taken to cover 9 km = 9/54×60 = 10 min.

Question 16 of 50
16. Question
A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. Find the average speed for first 320 km of tour.
Correct
Answer: Option B
Explanation:
We know Time = Distance/speedSo total time taken =
(160/64+160/80)=9/2hours
Time taken for 320 Km = 320∗2/9=71.11km/hrIncorrect
Answer: Option B
Explanation:
We know Time = Distance/speedSo total time taken =
(160/64+160/80)=9/2hours
Time taken for 320 Km = 320∗2/9=71.11km/hr 
Question 17 of 50
17. Question
Ram and Sham are running a race, Ram runs 25% faster than Sham and is able to allow Sham a lead of 7 meters to end a race in dead heat. Find the distance of the race.
Correct
Answer: Option B
Explanation:
Important to Note first – Dead Head means – run or finish a race at exactly level or at same time.From question it is clear that Ram runs faster than Sham by 25%,
So if Sham runs 100 meter in a given time then Ram will run 125 meter in that time.
So if Sham runs 4 meter then Ram will run 5 meter in given time (divide both by 25)
=> Ram can give Sham a lead of 1 meter in 5 meter race to finish race in dead heat.
Ratio of length of start given : length of race :: 1 : 5
As per question, start was given of 7 meter, So,
Length of race was 7 * 5 = 35.Incorrect
Answer: Option B
Explanation:
Important to Note first – Dead Head means – run or finish a race at exactly level or at same time.From question it is clear that Ram runs faster than Sham by 25%,
So if Sham runs 100 meter in a given time then Ram will run 125 meter in that time.
So if Sham runs 4 meter then Ram will run 5 meter in given time (divide both by 25)
=> Ram can give Sham a lead of 1 meter in 5 meter race to finish race in dead heat.
Ratio of length of start given : length of race :: 1 : 5
As per question, start was given of 7 meter, So,
Length of race was 7 * 5 = 35. 
Question 18 of 50
18. Question
A does half as much work as B in threefourth of the time. If together they take 18 days to complete the work, how much time shall B take to do it
Correct
Answer: Option C
Explanation:
Suppose B takes x dáys to do the work.
As per question A will take
2∗3/4∗x=3x/2days
(A+B)s 1 days work= 1/18
1/x + 2/3x = 1/18 or x = 30 daysIncorrect
Answer: Option C
Explanation:
Suppose B takes x dáys to do the work.
As per question A will take
2∗3/4∗x=3x/2days
(A+B)s 1 days work= 1/18
1/x + 2/3x = 1/18 or x = 30 days 
Question 19 of 50
19. Question
A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
Correct
Answer: Option C
Explanation:
Let A’s 1 day’s work = x and B’s 1 day’s work = y.
Then, x + y = 1/30 and 16x + 44y = 1.
Solving these two equations, we get: x =1/60and y =1/60
B’s 1 day’s work =1/60.
Hence, B alone shall finish the whole work in 60 days.Incorrect
Answer: Option C
Explanation:
Let A’s 1 day’s work = x and B’s 1 day’s work = y.
Then, x + y = 1/30 and 16x + 44y = 1.
Solving these two equations, we get: x =1/60and y =1/60
B’s 1 day’s work =1/60.
Hence, B alone shall finish the whole work in 60 days. 
Question 20 of 50
20. Question
An employer pays Rs. 30 for each day a worker works, and forfeits Rs. 5 for each day he is idle. At the end of 60 days, a worker gets Rs. 500. For how many days did the worker remain idle?
Correct
ANSWER:C
Explanation:
Suppose the worker remained idle for m days. Then, he worked for (60 – m) days.
30 (60 – m) – 5m = 500
1800 – 25m = 500
25m = 1300
m = 52
So, the worker remained idle for 52 days.Incorrect
ANSWER:C
Explanation:
Suppose the worker remained idle for m days. Then, he worked for (60 – m) days.
30 (60 – m) – 5m = 500
1800 – 25m = 500
25m = 1300
m = 52
So, the worker remained idle for 52 days. 
Question 21 of 50
21. Question
Rs.100 doubled in 5 years when compounded annually. How many more years will it take to get another Rs.200 compound interest?
Correct
Correct Answer – B
Explanatory AnswerRs.100 invested in compound interest becomes Rs.200 in 5 years.
The amount will double again in another 5 years.
i.e., the amount will become Rs.400 in another 5 years.
So, to earn another Rs.200 interest, it will take another 5 years.
Incorrect
Correct Answer – B
Explanatory AnswerRs.100 invested in compound interest becomes Rs.200 in 5 years.
The amount will double again in another 5 years.
i.e., the amount will become Rs.400 in another 5 years.
So, to earn another Rs.200 interest, it will take another 5 years.

Question 22 of 50
22. Question
A man saves Rs 200 at the end of each year and lends the money at 5% compound interest. How much will it become at the end of 3 years.
Correct
Answer: Option C
Explanation:
=[200 )]=662.02
Incorrect
Answer: Option C
Explanation:
=[200 )]=662.02

Question 23 of 50
23. Question
Albert invested amount of 8000 in a fixed deposit for 2 years at compound interest rate of 5 % per annum. How much Albert will get on the maturity of the fixed deposit.
Correct
Answer: Option D
Explanation:
=>(800*)=>
=>8820
Incorrect
Answer: Option D
Explanation:
=>(800*)=>
=>8820

Question 24 of 50
24. Question
Which of the following is the solution of 2x + 3 ≤ 9 in the real numbers?
Correct
If 2x +3 ≤ 9 then 2x ≤ 6 and x ≤ 3.
Incorrect
If 2x +3 ≤ 9 then 2x ≤ 6 and x ≤ 3.

Question 25 of 50
25. Question
Which of the following is the solution to in the real numbers?
Correct
Your answer is correct.
4 – x >2x 5
4 – 3x> 5
3x> – 9
x<3Incorrect
Your answer is correct.
4 – x >2x 5
4 – 3x> 5
3x> – 9
x<3 
Question 26 of 50
26. Question
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety of tea in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, what is the price of the third variety per kg ?
Correct
Explanation:
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed in the ratio 1 : 1
So their average price = =130.5=(126+135)2=130.5
Hence let’s consider that the mixture is formed by mixing two varieties of tea, one at Rs. 130.50 per kg and the other at Rs. xx per kg in the ratio 2 : 2, i.e., 1 : 1. Now let’s find out xx.
By rule of alligation,
(x153) : 22.5 = 1 : 1
=> x – 153 = 22.5
=> x = 153+22.5 = 175.5Incorrect
Explanation:
Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed in the ratio 1 : 1
So their average price = =130.5=(126+135)2=130.5
Hence let’s consider that the mixture is formed by mixing two varieties of tea, one at Rs. 130.50 per kg and the other at Rs. xx per kg in the ratio 2 : 2, i.e., 1 : 1. Now let’s find out xx.
By rule of alligation,
(x153) : 22.5 = 1 : 1
=> x – 153 = 22.5
=> x = 153+22.5 = 175.5 
Question 27 of 50
27. Question
In how many different ways can the letters of the word ‘OPTICAL’ be arranged so that the vowels always come together?
Correct
The word ‘OPTICAL’ has 7 letters. It has the vowels ‘O’,’I’,’A’ in it and these 3 vowels should always come together. Hence these three vowels can be grouped and considered as a single letter. That is, PTCL(OIA).
Hence we can assume total letters as 5 and all these letters are different.
Number of ways to arrange these letters
=5!=5×4×3×2×1=120=5!=5×4×3×2×1=120All the 3 vowels (OIA) are different
Number of ways to arrange these vowels among themselves
=3!=3×2×1=6=3!=3×2×1=6Hence, required number of ways
=120×6=720Incorrect
The word ‘OPTICAL’ has 7 letters. It has the vowels ‘O’,’I’,’A’ in it and these 3 vowels should always come together. Hence these three vowels can be grouped and considered as a single letter. That is, PTCL(OIA).
Hence we can assume total letters as 5 and all these letters are different.
Number of ways to arrange these letters
=5!=5×4×3×2×1=120=5!=5×4×3×2×1=120All the 3 vowels (OIA) are different
Number of ways to arrange these vowels among themselves
=3!=3×2×1=6=3!=3×2×1=6Hence, required number of ways
=120×6=720 
Question 28 of 50
28. Question
Look carefully for the pattern, and then choose which pair of numbers comes next.
17 32 19 29 21 26 23
Correct
Explanation: Here, there are two alternating patterns. The first begins with 17 and adds 2; the second begins with 32 and subtracts 3.
Incorrect
Explanation: Here, there are two alternating patterns. The first begins with 17 and adds 2; the second begins with 32 and subtracts 3.

Question 29 of 50
29. Question
complete the series 29. 6, 11, 21, 36, 56, … ?
Correct
Explanation:
Pattern is +5, +10, +15, + 20. So next will be 56+25 = 81
Incorrect
Explanation:
Pattern is +5, +10, +15, + 20. So next will be 56+25 = 81

Question 30 of 50
30. Question
If TAP is coded as SZO, then how is FREEZE coded ?
Correct
Answer: Option B
Explanation:
Clearly,T 1 = S
A 1 = Z
P 1 = OSo FREEZE will be,
F 1 E
R 1 Q
E 1 D
E 1 D
Z 1 Y
E 1 DIncorrect
Answer: Option B
Explanation:
Clearly,T 1 = S
A 1 = Z
P 1 = OSo FREEZE will be,
F 1 E
R 1 Q
E 1 D
E 1 D
Z 1 Y
E 1 D 
Question 31 of 50
31. Question
ELFA, GLHA, ILJA, _____, MLNA
Correct
Explanation:
The second and forth letters in the series, L and A, are static. The first and third letters consist of an alphabetical order beginning with the letter E.Incorrect
Explanation:
The second and forth letters in the series, L and A, are static. The first and third letters consist of an alphabetical order beginning with the letter E. 
Question 32 of 50
32. Question
CMM, EOO, GQQ, _____, KUU
Correct
Explanation:
The first letters are in alphabetical order with a letter skipped in between each segment: C, E, G, I, K. The second and third letters are repeated; they are also in order with a skipped letter: M, O, Q, S, U.Incorrect
Explanation:
The first letters are in alphabetical order with a letter skipped in between each segment: C, E, G, I, K. The second and third letters are repeated; they are also in order with a skipped letter: M, O, Q, S, U. 
Question 33 of 50
33. Question
If ‘eraser’ is called ‘box’, ‘box’ is called ‘pencil’, ‘pencil’ is called ‘sharpener’, and ‘sharpener’ is called ‘bag’, what will a child write with?
Correct
Answer / Explanation
Answer : D.A child will write with a ‘pencil’, and pencil is called ‘sharpener’. So, a child will write with a ‘sharpener’.
Incorrect
Answer / Explanation
Answer : D.A child will write with a ‘pencil’, and pencil is called ‘sharpener’. So, a child will write with a ‘sharpener’.

Question 34 of 50
34. Question
If in a certain code ROPE is coded as 6821, CHAIR is coded as 73456 what will be the code for CRAPE?
Correct
Clearly, in the given code, the alphabets are coded as follows.
R O P E C H A I
6 8 2 1 7 3 4 5So CRAPE is coded as 76421, So the answer is (2)
Incorrect
Clearly, in the given code, the alphabets are coded as follows.
R O P E C H A I
6 8 2 1 7 3 4 5So CRAPE is coded as 76421, So the answer is (2)

Question 35 of 50
35. Question
Pointing to a man, a woman said, “His mother is the only daughter of my mother.” How is the woman related to the man ?
Correct
Answer: Option A
Explanation:
Blood relation Analysis :
only daughter of my mother > means herselfSo she is his mother.
Incorrect
Answer: Option A
Explanation:
Blood relation Analysis :
only daughter of my mother > means herselfSo she is his mother.

Question 36 of 50
36. Question
If A + B means A is the brother of B; A x B means A is the son of B; and A % B means B is the daughter of A then which of the following means M is the maternal uncle of N?
Correct
Answer: Option D
Explanation:
Because the sex of O is not known.Incorrect
Answer: Option D
Explanation:
Because the sex of O is not known. 
Question 37 of 50
37. Question
What is the product of all the numbers in the dial of a telephone ?
Correct
Explanation :
Since one of the numbers on the dial of a telephone is zero, so the product of all the numbers on it is 0.Incorrect
Explanation :
Since one of the numbers on the dial of a telephone is zero, so the product of all the numbers on it is 0. 
Question 38 of 50
38. Question
A pineapple costs Rs. 7 each. A watermelon costs Rs. 5 each. X spends Rs. 38 on these fruits. The number of pineapples purchased is
Correct
EXplanation:
Let the number of pineapples and watermelons be x and y respectively.Then, 7x+5y=38 or 5y=(387x) or y=
Clearly, yis a whole number, only when (387x) is divisible by 5.
This happen when x=4.
Incorrect
EXplanation:
Let the number of pineapples and watermelons be x and y respectively.Then, 7x+5y=38 or 5y=(387x) or y=
Clearly, yis a whole number, only when (387x) is divisible by 5.
This happen when x=4.

Question 39 of 50
39. Question
In a college, the ratio of the number of boys to girls is 8 : 5. If there are 200 girls, the total number of students in the college is
Correct
Let the boy are 8x and Girls are 5x
=> 5x = 200
=> x = 40Total students = 8x+5x = 13x = 13(40) = 520
Incorrect
Let the boy are 8x and Girls are 5x
=> 5x = 200
=> x = 40Total students = 8x+5x = 13x = 13(40) = 520

Question 40 of 50
40. Question
A person incurs a loss of 5% be selling a watch for Rs. 1140. At what price should the watch be sold to earn 5% profit
Correct
Answer: Option C
Explanation:
Let the new S.P. be x, then.
(100 – loss%):(1st S.P.) = (100 + gain%):(2nd S.P.)=(95/1140=105/x)
=x=1260Incorrect
Answer: Option C
Explanation:
Let the new S.P. be x, then.
(100 – loss%):(1st S.P.) = (100 + gain%):(2nd S.P.)=(95/1140=105/x)
=x=1260 
Question 41 of 50
41. Question
The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:
Correct
Answer: Option D
Explanation:
Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135 …. (i)
A + B = (40 x 2) = 80 …. (ii)
B + C = (43 x 2) = 86 ….(iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 …. (iv)
Subtracting (i) from (iv), we get : B = 31.
B’s weight = 31 kg.
Incorrect
Answer: Option D
Explanation:
Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135 …. (i)
A + B = (40 x 2) = 80 …. (ii)
B + C = (43 x 2) = 86 ….(iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 …. (iv)
Subtracting (i) from (iv), we get : B = 31.
B’s weight = 31 kg.

Question 42 of 50
42. Question
The average of six numbers is X and the average of three of these is Y.If the average of the remaining three is z, then
Correct
Answer: Option B
Explanation:
X =((3y+3z)/6)
or
2X= y + zIncorrect
Answer: Option B
Explanation:
X =((3y+3z)/6)
or
2X= y + z 
Question 43 of 50
43. Question
Evaluate :
28% of 400 + 45 % of 250
Correct
ANSWER: B
Explanation:
28% of 400 + 45 % of 250
= (28/100 *400 + 45/100 * 250)
= (112 + 112.5)
= 224.5Incorrect
ANSWER: B
Explanation:
28% of 400 + 45 % of 250
= (28/100 *400 + 45/100 * 250)
= (112 + 112.5)
= 224.5 
Question 44 of 50
44. Question
Look at this series: 544, 509, 474, 439, … What number should come next?
Correct
Answer: Option A
Explanation:
This is a simple subtraction series. Each number is 35 less than the previous number.
Incorrect
Answer: Option A
Explanation:
This is a simple subtraction series. Each number is 35 less than the previous number.

Question 45 of 50
45. Question
A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. Find the average speed for first 320 km of tour.
Correct
Answer: Option B
Explanation:
We know Time = Distance/speedSo total time taken =
(160/64+160/80)=9/2hours
Time taken for 320 Km = 320∗2/9=71.11km/hrIncorrect
Answer: Option B
Explanation:
We know Time = Distance/speedSo total time taken =
(160/64+160/80)=9/2hours
Time taken for 320 Km = 320∗2/9=71.11km/hr 
Question 46 of 50
46. Question
Rs.100 doubled in 5 years when compounded annually. How many more years will it take to get another Rs.200 compound interest?
Correct
Correct Answer – B
Explanatory AnswerRs.100 invested in compound interest becomes Rs.200 in 5 years.
The amount will double again in another 5 years.
i.e., the amount will become Rs.400 in another 5 years.
So, to earn another Rs.200 interest, it will take another 5 years.
Incorrect
Correct Answer – B
Explanatory AnswerRs.100 invested in compound interest becomes Rs.200 in 5 years.
The amount will double again in another 5 years.
i.e., the amount will become Rs.400 in another 5 years.
So, to earn another Rs.200 interest, it will take another 5 years.

Question 47 of 50
47. Question
What will be the compound interest on Rs. 25000 after 3 years at the rate of 12 % per annum
Correct
Answer: Option A
Explanation:
25000*(1+)^3
25000*
=35123.20So Compound interest will be 35123.20 – 25000
= Rs 10123.20Incorrect
Answer: Option A
Explanation:
25000*(1+)^3
25000*
=35123.20So Compound interest will be 35123.20 – 25000
= Rs 10123.20 
Question 48 of 50
48. Question
Two vessels A and B contain spirit and water in the ratio 5 : 2 and 7 : 6 respectively. Find the ratio in which these mixtures be mixed to obtain a new mixture in vessel C containing spirit and water in the ratio 8 : 5 ?
Correct
Explanation:
Let Cost Price(CP) of 1 litre spirit be Rs.1
Quantity of spirit in 1 litre mixture from vessel A =
Cost Price(CP) of 1 litre mixture from vessel A = Rs. =
Quantity of spirit in 1 litre mixture from vessel B=
Cost Price(CP) of 1 litre mixture from vessel B = Rs. =
Quantity of spirit to be obtained in 1 litre mixture from vessel C =
Cost Price(CP) of 1 litre mixture from vessel C(Mean Price) = Rs. =
By rule of alligation,
=> Mixture from Vessel A : Mixture from Vessel B
= = 7 : 9
Incorrect
Explanation:
Let Cost Price(CP) of 1 litre spirit be Rs.1
Quantity of spirit in 1 litre mixture from vessel A =
Cost Price(CP) of 1 litre mixture from vessel A = Rs. =
Quantity of spirit in 1 litre mixture from vessel B=
Cost Price(CP) of 1 litre mixture from vessel B = Rs. =
Quantity of spirit to be obtained in 1 litre mixture from vessel C =
Cost Price(CP) of 1 litre mixture from vessel C(Mean Price) = Rs. =
By rule of alligation,
=> Mixture from Vessel A : Mixture from Vessel B
= = 7 : 9

Question 49 of 50
49. Question
A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
Correct
Number of runs made by running = 110 – (3 x 4 + 8 x 6)
= 110 – (60)
= 50.
Required percentage = 50 x 100 =
Incorrect
Number of runs made by running = 110 – (3 x 4 + 8 x 6)
= 110 – (60)
= 50.
Required percentage = 50 x 100 =

Question 50 of 50
50. Question
Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg.
Correct
CP of 1kg 1st kind rice = Rs.7.20
CP of 1kg 2nd kind rice = Rs.5.70
CP of 1kg mixed rice = Rs.6.30By rule of alligation,
Required Ratio = .6 : .9 = 6:9 = 2:3
Incorrect
CP of 1kg 1st kind rice = Rs.7.20
CP of 1kg 2nd kind rice = Rs.5.70
CP of 1kg mixed rice = Rs.6.30By rule of alligation,
Required Ratio = .6 : .9 = 6:9 = 2:3
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Coming Soon ! Click HereHow to aptitude test help in career planning
Why it is important for every student to understand the meaning of aptitude. Aptitude means that regular, learned or ability of a person to perform certain tasks. Aptitude tests inculcate many factors like Numerical reasoning, verbal reasoning, abstract reasoning, speed, accuracy, and other such abilities. Aptitude is considered to finding the strengths and weakness of the candidate.
In this section, how to face the online test in the exam like Bank (Clerk, PO, SO) and others. These tests are for growing the skills in the different sections for the exams. Candidates prepare exams. Enhancing your skills by giving these tests for getting high score in above mentioned exams. These tests help in interviews, campus recruitment process etc.
Aptitude test consists of following section like Quantitative aptitude, reasoning, English, Computers and Marketing which given in exams. These sections have multiple choice questions (only one answer).
Online aptitude test is basically image of exam which is same as the real exam. This test will be encouraging the candidate to get accuracy in the mentioned exams. After giving the aptitude test, you get your score and rank in the group of candidates. Candidate can check which section has low score from the individually score.
The use of aptitude tests to screen potential job applicants has long been standard practice across many different sectors. As such they have become an important and integral part of the overall interview process.
In this article,how to important the online aptitude test in IBPS bank exam.In the present time,every government department conducts the exam through online and not offline.
What is Online Aptitude Test
Online aptitude test is the most popular process for selection candidates in employment sector or education sector on the older method i.e. offline.The new traditions is that for taking the exam in IBPS is online aptitude test.In the online test have low cost,minimum efforts as compare to the traditional examination procedure was costly, maximum effort very lengthy process.An online test is a practice paper before the actual exam.Attempting the online test get the idea of actual pattern of exam because it tells you about your level of preparation.Most importantly, it also tells you the areas which needs your attention.
There are some organizations which conducts the online test are Institute of Banking Personnel Selection (IBPS) Common Written Entrance test, State Bank of India (SBI) Entrance Exams, University Grants Commission (UGC), Regional Rural Bank Entrance Exams, Railway Recruitment Board (RRB) Exam, Staff Selection Commission (SSC) Entrance Test, Common Aptitude Test (CAT) Entrance Exam, Life Insurance Corporation (LIC) Entrance Exams, Union Public Service Commission (UPSC), University exams, All types of Interview jobs, Information Technology (IT) Exams, Integrated Common Entrance Test (ICET) and many other exams.
Importance of Online Aptitude Test
1) Helps you to finish your paper in time.
2) Online Test helps students to give attention on weak portion of the examination.
3) Revision is the key to remember all that you have studied.
4) Online test helps in revision of full syllabus.
5) Most of the online test series is designed in a way which shows the real image .
Tips to pass your aptitude test
 Practice Aptitude tests online.
 Get all the right information.
 Practice as many aptitude tests as you can.
Test structures for online aptitude test
Score and marking
In this we will check the score and marks in each section.You can evaluate that which section is weak.
Negative Marking
Many aptitude tests incorporate negative marking. If this is the case, you will normally be told beforehand. In any test that does incorporate negative marking, you must not guess answers, even if you are under extreme time pressure, as you will undo your chances of passing.